Answer:
How far should he ride on each of the four days to reach his goal?
1st day:
miles
2nd day:
miles
3rd day:
miles
4th day:
miles
Step-by-step explanation: As the problem says,
is the number of miles he rides on the first day. Let's start off with that.
1st day:
miles
He want to ride 1.5 times as far as he rode the day before... no 1.5 more, but 1.5 <em>times</em> as far as he rode the day before; you would multiply 1.5 with the previous day's length.
2nd day: 
Then you multiply
to
to get the third day's.
3rd day: 
4th day: 
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Phew! Gavin wants to ride a total of 65 miles over these four days, so if Gavin added all the miles of the four days, he should get 65...
1st+2nd+3rd+4th=65




Yes! Now that we've got the hard part done... substitute 8 for ever single
.
1st day:
miles
2nd day:
miles
3rd day:
miles
4th day:
miles
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Checking my answer:
Just add the miles!


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Hope that helps! :D
Answer:
same amount of money
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
u can use Pythagorean theorem a2 + b2 =c2. c2 is the length of the hypotenuse. plug in 3 for a and 15 for b. 3 squared plus 15 squared equals c squared. 9+225= c2. 234=c2. answer is D. the square root of 234
Answer:
10 Seconds
Step-by-step explanation:
Speed of Elene = 3m/s
Speed of Abbi = 2m/s
Let the time be t seconds taken by Elene to catch abbi.
Distance for any speed S and time is calculated by formula given below
Distance = speed * time
- distance covered by Elene in time t = 3m/s * t = 3t m -->equation A
- distance covered by Abbi in time t = 2m/s* t = 2t m --> equation B
Since it is given that Elene has given abbi 10 m head start it means that
Elene has to run extra 10 meters than Abbi to catch abbi.
Thus we can say that
distance run by Elene = 10 m + distance run by Abbi
Substituting that value distance run by Elene from equation A
and distance run by Abbi from equation B
we have
3t = 2t +10
=>3t - 2t = 10
=> t = 10
Therefore it will take 10 second for elene to catch abbi.