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Igoryamba
2 years ago
7

Which equation is the inverse of y = 9x2 – 4? y = StartFraction plus-or-minus StartRoot x + 4 EndRoot Over 9 EndFraction y = plu

s-or-minus StartRoot StartFraction x Over 9 EndFraction + 4 EndRoot y = StartFraction plus-or-minus StartRoot x + 4 EndRoot Over 3 EndFraction y = StartFraction plus-or-minus StartRoot x EndRoot Over 3 EndFraction + two-thirds
Mathematics
2 answers:
andre [41]2 years ago
8 0

Option C: y=\pm\frac{\sqrt{x+4}}{3} is the inverse of the function

Explanation:

The given function is y=9 x^{2}-4

We need to determine the inverse of the function.

To determine the inverse of the function, we need to interchange the values of x and y and solve for y.

Let us interchange the variables x and y in the function y=9 x^{2}-4, we have,

x=9 y^{2}-4

Adding both sides of the equation by 4, we have,

x+4=9 y^{2}

Dividing both sides of the equation by 9, we have,

\frac{x+4}{9} =y^2

Switch sides, we have,

y^2=\frac{x+4}{9}

Taking square root on both sides of the equation, we have,

y=\pm\frac{\sqrt{x+4}}{3}

Thus, the inverse of the function is y=\pm\frac{\sqrt{x+4}}{3}

Therefore, Option C is the correct answer.

Lisa [10]2 years ago
3 0

Answer:

A

Step-by-step explanation:

This answer is right, the one above it is wrong

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the area of the trapezoid is (3/4x-1/4) square centimeters. two pairs of expressions that represent possible lengths of bases. h
slava [35]
Let a and be be the bases. 
The formula of the area is the following :
\frac{a+b}{2}\times h= \frac{a+b}{2}\times\frac{1}{2}=\frac{a+b}{4}
Equating we get the equation:
\frac{a+b}{4} = \frac{3}{4} x- \frac{1}{4} = \frac{3x+1}{4}
So, identifying we get two possible expression:
a=3x,b=1
4 0
2 years ago
Solve the following multiplication and division problems. a. 8 T. 1,398 lb. 14 oz. × 6 b. 349 lb. 6 oz. ÷ 130 c. 6 T. 294 lb. ÷
tester [92]

Answer:  a) 278382 oz

b) 43 oz

c) 64.1 oz

Step-by-step explanation:

a) 8 T. 1,398 lb. 14 oz. × 6

First we need to change it in 'oz'.

As we know that

1\ ton=32000\ oz\\\\1\ lb=16\ oz

so, it becomes,

8\times 32000+1398\times 16+14\ oz\\\\=278382\ oz

8 T. 1,398 lb. 14 oz. × 6 becomes

278382\times 6\\\\=1670292\ oz

b) 349 lb. 6 oz. ÷ 130

It becomes,

349\times 16+6\ oz\\\\=5590\ oz\\\\\text{ at last it becomes}\\\\=\frac{5590}{130}\\\\=43\ oz

c) 6 T. 294 lb. ÷ 3,071

First it becomes,

6\times 32000+294\times 16\ oz\\\\=196704\ oz

At last it becomes,

\frac{196704}{3071}\\\\=64.1\ oz

Hence, a) 278382 oz

b) 43 oz

c) 64.1 oz

6 0
2 years ago
Read 2 more answers
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0
2 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
statuscvo [17]
Let's start by visualising this concept.

Number of grains on square:
1   2   4   8   16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
T_n = ar^{n - 1}
T_{15} = 2^{14} = 16384

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
S_n = \frac{a(r^{n} - 1)}{r - 1}
S_{15} = \frac{2^{15} - 1}{2 - 1}
S_{15} = 2^{15} - 1 = 32767

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.
6 0
2 years ago
Read 2 more answers
Which is the smallest 0.37 0.194 0.6 0.473 0.29
wolverine [178]

0.37

0.194

0.6

0.473

0.29

the smallest digit at tenth place is 1 in 0.194, so 0.194 is the smallest here

4 0
2 years ago
Read 2 more answers
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