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Fynjy0 [20]
2 years ago
9

the area of the trapezoid is (3/4x-1/4) square centimeters. two pairs of expressions that represent possible lengths of bases. h

eight is 1/2 centimeters
Mathematics
1 answer:
slava [35]2 years ago
4 0
Let a and be be the bases. 
The formula of the area is the following :
\frac{a+b}{2}\times h= \frac{a+b}{2}\times\frac{1}{2}=\frac{a+b}{4}
Equating we get the equation:
\frac{a+b}{4} = \frac{3}{4} x- \frac{1}{4} = \frac{3x+1}{4}
So, identifying we get two possible expression:
a=3x,b=1
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A zookeeper is monitoring the population of birds. The flock needs to have exactly three times more females than males to thrive
KIM [24]

Answer:

The constraints are

0 < x\leq 20  and 0 < y\leq 60

Step-by-step explanation:

Let

x ----> represent the number of male birds

y ----> represent the number of female birds

we know that

The flock needs to have exactly three times more females than males to thrive

so

y=3x ----> equation A

The zoo only has room for a maximum of 20 male birds

so

0 < x\leq 20 ----> inequality B

we know that

The maximum number of male birds is 20

For x=20

substitute in the equation A

y=3(20)=60

so

The maximum number of female birds is 60

so

0 < y\leq 60 ----> inequality C

therefore

The constraints are

0 < x\leq 20  and 0 < y\leq 60

4 0
2 years ago
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Answer: This is what Khan Academy said the answer was

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A train leaves at 08.43 and arrives at its destination at 09.23. If the train travelled 73 km, what was it's average speed in km
serg [7]

Answer: 109.5 km/ hr

Step-by-step explanation:

Distance = 73 km

Time = 40 minutes = 40/60 = 2/3 hours

Speed = Distance / time

= 73 / 2/3

= 73 x 3/2 = 219 / 2 = 109.5 km/hr

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6x2y – 2x2y – 10x2y + 8x2y =
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A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0
2 years ago
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