The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.
For more context let's look at the first equation in the problem that we can apply this to:

Through zero property we know that the factor

can be equal to zero as well as

. This is because, even if only one of them is zero, the product will immediately be zero.
The zero product property is best applied to
factorable quadratic equations in this case.
Another factorable equation would be

since we can factor out

and end up with

. Now we'll end up with two factors,

and

, which we can apply the zero product property to.
The rest of the options are not factorable thus the zero product property won't apply to them.
Answer:
Mark the point of intersection S of circles R and P, and construct line QS.
Step-by-step explanation:
In the figure attached, the problem is shown. The construction of the tangent lines from point Q to circle P is almost done. The last step is to draw the lines that pass through point Q and the intersection of the circles.
Answer:
see the explanation
Step-by-step explanation:
we know that
A gross is equal to 120 ones or ten dozen
what is 15 tens - 1 gross
we know that
15 tens means ----> That you are adding 10, 15 times or multiplying 10 by 15, which gives you

1 gross means ---> That you are adding 10, 12 times or multiplying 10 by 12
which gives you

so
The algebraic expression of 15 tens - 1 gross is equal to

Convert to word expression
3 tens
Answer:
Part A) 
Part B) She will spend more than 
Step-by-step explanation:
Let
p-----> the number of hamburger patties
Part A) Luna has to buy at least 16 packages for an upcoming picnic


Part B) Suppose she actually needs more than 150 hamburgers. How much will she spend?
Let
c---------> the total cost
step 1
Divide 150 hamburgers by 8 (a package of hamburgers)
so

round to the nearest whole number
----> the minimum number of packages
step 2


Answer:
The answer is 3
Step-by-step explanation:
B/c 8+2=10 just add one more and 2+1=3