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2 years ago

5

To take a taxi, it costs \$3.00$3.00dollar sign, 3, point, 00 plus an additional \$2.00$2.00dollar sign, 2, point, 00 per mile t

raveled. You spent exactly \$20$20dollar sign, 20 on a taxi, which includes the \$1$1dollar sign, 1 tip you left.

1 answer:

djverab [1.8K]2 years ago

5 0

Answer 8 miles

Step-by-step explanation:

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The derivative of the function B is given by B′(t)=8e0.2cost , and B(2.2)=4.5 . If the linear approximation to B(t) at t=2.2 is

Elis [28]

Answer:

The linear approximation of B(t) at t = 2.2 estimates B(t) = 9 for t = 2.8328

Step-by-step explanation:

b'(2.2) = 8 * e^(0.2cos(2.2)) = 7.1117 and b(2.2) = 4.5. The linear approximation of B(t) at t = 2.2 is

L(t) = 7.1117*(t-2.2) + 4.5

We want t so that L(t) = 9

9 = 7.1117*(t-2.2) + 4.5

4.5 = 7.1117 *(t-2.2)

t-2.2 = 4.5/7.1117 = 0.6327601

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2 years ago

After a 5% pay raise , Hermione is earning $21,000 per year. What was she earning before the pay raise?

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Answer:

$\$20,000$

Step-by-step explanation:

Let

x -----> Hermione was earning before the pay raise

we know that

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so

The linear equation that represent this problem is

$1.05x=21,000$

Solve for x

Divide by 1.05 both sides

$x=21,000/1.05$

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Ummi is setting up an aquarium in the shape shown here. She fills it

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Step-by-step explanation:

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In the land of Ink, the money system is unique. One Trinket is equal to 4 Blinkets, and 3 Blinkets are equal to 7 Drinkets. In T

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2 years ago

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Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is th

gtnhenbr [62]

Answer:

a) t = 4

b) v = pi j + 5 k

c) rt = 1i + (pi t) j + (20 +5t )k

Step-by-step explanation:

You have the following vector equation for the position of a particle:

$r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}$ (1)

(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.

For a height of 20 you have:

$5t=20\\\\t=\frac{20}{5}=4$

(b) The velocity of the particle is the derivative, in time, of the vector position:

$v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}$ (2)

and for t=4 (height = 20):

$v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}$

(c) The vector parametric equation of the tangent line is given by:

$r_t(t)=r_o+vt$ (3)

ro: position of the particle for t=4

$r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}$

Then you replace ro and v in the equation (3):

$r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}$

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2 years ago