The volume given is 3Pi(x^3) and the radius is x.
The formula for the volume of a cone is V= [1/3]Pi(r^2)*height
=> [1/3]Pi (r^2) x = 3Pi(x^3) =>
(r^2)x = 3*3(x^3) => (r^2)x = 9(x^3) => (r^2) = 9x^2 =>
r = sqrt[9x^2] = 3x.
<span>Answer: r = 3x</span>
Answer:
Ratio of the perimeters =3:1
Step-by-step explanation:
We have given that : Ratio of the sides of two squares is 3:1
To find : Ratio of their perimeters
Solution : Let the length of the sides are 3:1 = 3x : x
Formula of perimeter of square = 4(side)
Using the formula ,
Perimeter of 1 square = 4×3x= 12x
Perimeter of 2 square = 4×x= 4x
Ratio of the perimeter of 1 square and 2 square = 12x : 4x
= 3 : 1
All u need to do is subtract the bigger number from the smaller one
$250 c+ $ 180 g > $ 950
<u>Step-by-step explanation:</u>
As a cryptographer (c), Miyoko earns per day = $ 250
As a geologist (g) , Miyoko earns per day = $ 180
So the equation comes to be $250 c+ $ 180 g = $ 950
The equation can be rewritten to find c as, (950-180 g) / 250
The equation can be rewritten to find g as, (950 - 250 c) / 180
Plugin different values of c and g in the above 2 equations, we can find that ,
To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.
Answer:
0.25
Step-by-step explanation:
72% of courses have final exams and 46% of courses require research papers which means probability of 0.72 for courses that have final exams and 0.46 for courses that require research papers.
31% of courses have a research paper and a final exam, which means probability of 0.31 for both courses with exams and research papers, using Venn diagram approach, find picture attached to the solution.
P(R or E) = P(R) + P(E) - P(R and E), which gives:
P(R or E) = 0.15 + 0.41 - 0.31
P(R or E) = 0.25.
