Answer:
No you can't because just like multiplication, you cant divide anything by zero.
Step-by-step explanation:
You must evaluate the function f first. Division by 0 is undefined.
Therefore, The composition cannot be evaluated.
Answer:
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
Total outcomes:
100 customers
Desired outcomes:
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.
Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Answer:
No multiplying both quantities in the ratio 60 : 36 by 1 would not give the answer .
But multiplying both quantities in the ratio 60 : 36 by 1/6 would solve it.
Step-by-step explanation:
Multiplying any number or ratio by 1 gives the same answer no matter what the expression or how much bigger the number is.This will not give the solution .
If it is multiplied with a fraction like 1/6 that would give the correct answer.
Multiplying it with 1/6 reduces the ratio and gives a better estimate.
A:B
60:36
60*1/6: 36*1/6
10: 6
Meaning that for a total of 16 there are 10 of category A and 6 of category B.
But if we do the same procedure with the answer is same which does not solve the question.
A:B
60:36
60*1: 36*1
60: 36
Answer:
109.9 ft
Step-by-step explanation:
The length of an arc that is 1/4 of a circle of radius 70 ft is ...
s = rθ
s = (70 ft)(π/2) = 35π ft ≈ 109.9557 ft
The best answer choice appears to be 109.9 feet.
Answer: The answer is 30%.
Step-by-step explanation: Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.
We have the following four possible cases -
(i) All 3 are light users.
(ii) 1 is a light user and 2 are heavy users.
(iii) 2 are light users and 1 is a heavy user.
(iv) All 3 are heavy user.
Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

Thus, the probability is 30.