Answer:
a)38760
b)5005
c)210
Step-by-step explanation:
Given that
20 identical sticks
We have to 6 of them
a)
The number of choice will be 
.
b)
The number of choices if no two of the chosen sticks can be consecutive will be 
.
c)
|xx|xx|xx|xx|xx|
Total seven positions are available
So
4-0-0-0-0-0-0 7!/6!=7
3-1-0-0-0-0-0 7!/5!=42
2-2-0-0-0-0-0 7!/2!5!=21
2-1-1-0-0-0-0 7!/2!4!=105
1-1-1-1-0-0-0 7!/4!3!=35
Now by adding all 7+42+21+105+35=210
The equation will be y=4/x. u can make the table of variables by inserting the values of x in the equation. for suppose here, if x=1 then y=4 , x=2 then y=2 and so on.
Let's convert the task into an example, simplifyng which will make us able to get the answer.
So, according to the task:
![\sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} = \sqrt[1/ 9 ]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%0A%0A%3D%20%20%20%5Csqrt%5B1%2F%209%20%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20)
Now we can simplify:
![\sqrt[1/9]{x} + 1/9+1/9+1/9 = x^{4/9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2B%201%2F9%2B1%2F9%2B1%2F9%0A%0A%3D%20x%5E%7B4%2F9%7D%20)
So the answer is <span>
C:x to the four ninths power</span>
There is 75% decrease.
Step-by-step explanation:
Given,
Old value = 688 qt
New value = 172 qt
Change = New value - Old value
Change = 172 - 688
Change = -516 qt
The negative sign indicates decrease.
Decrease percent = 
Decrease percent = 
Decrease percent = 
Decrease percent = 75%
There is 75% decrease.
Keywords: division, subtraction
Learn more about subtraction at:
#LearnwithBrainly
Answer:
a. 205320
b. 34220
c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
Step-by-step explanation:
a) The number of ways to dustribute exams among the TA's is:
n / (n - r)!
n= number of things to choose from
r= Choosing r number
60P3= 60! / (60 - 3)!
(60)(59)(58)(57)! / (57)!
=205320
B) The number of ways to dustribute the exams among the TA's is:
n! /(n - r)! r!
60C3= 60! /(60 - 3)! 3!
= 60!/ 57! 3!
= 60 × 59 × 58 / 3 × 2 × 1
= 34220
C) The required number of ways is:
60C25 + 60C20 + 60C15
= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
