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ser-zykov [4K]
1 year ago
13

1. Identify the lateral area and surface area of a regular square pyramid with base edge length 5 in. and slant height 9 in.

Mathematics
1 answer:
zlopas [31]1 year ago
6 0
1. C
L=1/2(Pxl)
L=1/2(20x9)
L=1/2(180)
L=90

SA=1/2(Pxl)+B
SA=90+5^2
SA=115

B, A, C, B.
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Find the 89th term of 25,35,45
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The 89th term would be 895.

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A warehouse store sells 4.5​-ounce cans of tuna in packages of 3. A package of 3 cans costs ​$4.32. The store also sells 3.5​-ou
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Answer:

The 6.5​-ounce cans offer the largest size at a fair cost and is the best to buy.

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Size of the 4.5​-ounce cans of tuna in package = 4.5 × 3 = 13.5 ounce

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Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t
SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be h meters and h= h_1+h_s.

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ.                                        In ΔSPR.

⇒ tan(60) = \frac{h_1}{x} ...equation (i)        ⇒ tan (30)=\frac{h_1}{x+50}  ...equation (ii)

Dividing equation (i) and (ii)

⇒ \frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}

⇒ 3 = \frac{x+50}{x}

⇒ 3x=x+50

⇒ 3x-x=50

⇒ 2x=50

⇒ x=\frac{50}{2}

⇒ x=25 meters

To find h_1 plugging x=25 in equation (i)

⇒ h_1=x\times tan(60)

⇒ h_1=25\times 1.73

⇒ h_1=43.25 meters

The height of the cliff from ground :

⇒ h= h_1+h_s

⇒ h= 43.25+1.8

⇒ h=45.05 meters

The cliff is 45 m tall to the nearest meter.

8 0
2 years ago
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