Two distinct roots means two real solutions for x (the parabola needs to cross the x-axis twice)
Vertex form of a quadratic equation: (h,k) is vertex
y = a(x-h)^2 + k
The x of the vertex needs to equal 3
y = a(x-3)^2 + k
In order to have two distinct roots the parabola must be (+a) upward facing with vertex below the x-axis or (-a) downward facing with vertex above the x-axis. Parabolas are symmetrical so for an easy factorable equation make "a" 1 or -1 depending on if you want the upward/downward facing one.
y = (x-3)^2 - 1
Vertex (3,-1) upwards facing with two distinct roots 4 and 2
y = x^2 -6x + 9 - 1
y = x^2 -6x + 8
y = (x - 4)(x - 2)
1) find the perfect square closest to the number
2) take that square root, and then divide your number by that number
3) take the average of the perfect square root (the whole number) and the result of dividing your original number by that root.
Example: Approximate square root of 27
Closest perfect square: 25
Square root: 5
27 ÷ 5 = 5.4
Average between 5 and 5.4 = 5.20
5.2² = 27.04. Fast and not a bad approximation!
Answer:
The last answer, D
Step-by-step explanation:
i got it right on ed
Answer:
Down below
Step-by-step explanation:
