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Rzqust [24]
2 years ago
10

The cost of a cab ride is $10 for the first mile or part of a mile. It costs $3 for each additional mile or part of a mile and a

ll cab rides are less than six miles. The cost is modeled by the function C(m), where "m" is the number of miles. The driver's pay "P" is a function of the cost "C" and is modeled by P(C) = 0.60C. What is the domain of P(C)? A) {1, 2, 3, 4, 5} B) {10, 13, 16, 19, 22, 25} C) {any positive real number less than 6} D) {any positive real number less than 25}
Mathematics
2 answers:
Vaselesa [24]2 years ago
8 0

Answer:

B) {10, 13, 16, 19, 22, 25}

Step-by-step explanation:

The given function is:

P(C) = 0.60C

Here C represents the cost of the cab ride. It is given that the cost of cab ride is $ 10 for the first mile and $3 for each additional mile or part of the mile.

So,

For upto first mile, cost = $ 10

For upto first 2 miles, cost = $ 10 + $ 3 = $ 13

For upto first 3 miles, cost = $ 13 + $ 3 = $ 16

For upto first 4 miles, cost = $ 16 + $ 3 = $ 19

For upto first 5 miles, cost = $ 19 + $ 3 = $ 22

For upto first 6 miles, cost = $ 22 + $ 3 = $ 25

The cab ride must be less than 6 miles. So even if the ride is more than 5 miles but less than 6 miles, still the cost will be $ 25.

This means, the values that C can take are 10, 13, 16, 19, 22 and 25

Since, P(C) = 0.60C, takes C as an input, the domain of C will be all the possible values that C can take.

Therefore, the domain of P(C) will be: {10, 13, 16, 19, 22, 25}

Andrej [43]2 years ago
3 0

Answer:

The answers B

Step-by-step explanation:

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We have a property for odd functions, which is given below. Let f(x) be an odd function then it must satisfy the below - mentioned property.

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C. 2 is less than or equal to x

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What is the zero in the quadratic function f(x)= 9x^2-54x-19?
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Step-by-step explanation:

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8 0
2 years ago
A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip. On the return route, the boat trav
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<em><u>The intervals included in solution are:</u></em>

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

<em><u>Solution:</u></em>

Given that,

A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip

On the return route, the boat travels against the current, decreasing the boat's rate by 10 mph

The group needs to travel an average of at least 24 mph

<em><u>Given inequality is:</u></em>

\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}

<em><u>We have to solve the inequality</u></em>

\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}\\\\\frac{2}{x}  - 10\geq \frac{2}{24}

\mathrm{Subtract\:}\frac{2}{24}\mathrm{\:from\:both\:sides}\\\\\frac{2}{x}-10-\frac{2}{24}\ge \frac{2}{24}-\frac{2}{24}\\\\Simplify\\\\\frac{2}{x}-10-\frac{2}{24}\ge \:0

\frac{2}{x}-\frac{10}{1}-\frac{2}{24} \geq 0\\\\\frac{ 2 \times 24}{x \times 24} -\frac{10 \times 24}{1 \times 24} - \frac{2 \times x }{24 \times x}\geq 0\\\\\frac{48}{24x}-\frac{240x}{24x}-\frac{2x}{24x}\geq 0\\\\Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions\\\\\frac{48-240x-2x}{24x}\geq 0\\\\Add\:similar\:elements\\\\\frac{48-242x}{24x}\ge \:0

\mathrm{Multiply\:both\:sides\:by\:}24\\\\\frac{24\left(48-242x\right)}{24x}\ge \:0\cdot \:24\\\\Simplify\\\\\frac{48-242x}{x}\ge \:0\\\\Factor\ common\ terms\\\\\frac{-2\left(121x-24\right)}{x}\ge \:0\\\\\mathrm{Multiply\:both\:sides\:by\:}-1\mathrm{\:\left(reverse\:the\:inequality\right)}

When we multiply or divide both sides by negative number, then we must flip the inequality sign

\frac{\left(-2\left(121x-24\right)\right)\left(-1\right)}{x}\le \:0\cdot \left(-1\right)\\\\\frac{2\left(121x-24\right)}{x}\le \:0\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{\frac{2\left(121x-24\right)}{x}}{2}\le \frac{0}{2}\\\\Simplify\\\\\frac{121x-24}{x}\le \:0

\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{121x-24}{x}\\

This is attached as figure below

From the attached table,

\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0\\\\0

<em><u>Therefore, solution set is given as</u></em>:

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

8 0
2 years ago
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