Answer:
A=8.4063
Step-by-step explanation:
Be the functions:
according the graph:
=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20%3D3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%3D3%28%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%29%3D3%5Blnx-%5Cfrac%7B1%7D%7Bx%7D%5D%281-7%29%3D3%5B%28ln7-ln1%29-%28%5Cfrac%7B1%7D%7B7%7D-1%29%5D%3D3%5B%281.945-0%29-%280.1428-1%29%5D%3D3%2A%281.945%2B0.8571%29%3D3%2A2.8021%3D8.4063u%5E%7B2%7D)
The question does not present the options, but this does not interfere with the resolution
we have that
y=3(x-2)²-(x-5)²
y=3(x²-4x+4)-(x²-10x+25)
y=3x²-12x+12-x²+10x-25
y=(3x²-x²)+(-12x+10x)+(12-25)
y=2x²-2x-13
y+13=2x²-2x
y+13=2(x²-x)
y+13+0.50=2(x²-x+0.25)
y+13.50=2(x-0.5)²------> this is the equation in the vertex form
the vertex is the point (0.5,-13.50)
Divide the price by the number of months to find the monthly rate.
<span>$237.36 ÷ 24 = $9.89 per month </span>
<span>$184.50</span><span> ÷ 18 = $10.25 per month
The two year club, Aqua Plus is cheaper
</span>
To arrive at the answer, I graphed the piecewise function using a graphing calculator, then evaluated it at x=38 and x=52. I drew a line at y=445 and found the point of intersection on the graph.
a) The difference between earnings for 52 hours ($580) and earnings for 38 hours ($380) is
$200.
b) An employee must work
43 hours to earn $445.
Answer:
The anwerss to the question are
(A) P(No less than two people use their phones while driving) = 0.1225
(B) P(The probability that no more than one person of the three people use their cell phone while driving) = 0.147875
Step-by-step explanation:
The given relations are
Percentage of motorists that routinely drive while sing their phone = 35 %
The probaboloty that if a peerson is random;ty selected from a group of hudred person routinely uses their phone wjile friving P(phone) = 35
The probability that a motorist randomly selected fron a set of 100 do not routinely use thir phones while driving = P(No celll phone) = 65
Then the probability that when three people are selected at random at least two people of the three people use their cell phone while driving is
P(phone) = 35/100m = 0.35
P(No celll phone) = 65/100 = 0.65
(A) Probability of at least two of three use their phones whle driving is
0.35×0.35×0.65 +0.35×0.35×0.35 = 0.1225
(B) The probability of only one person out of three seted use their phones while driving is
(0.35)(0.65)(0.65) = 0.147875
