Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

Answer 1

Answer:

The equation of the line in standard form is

$x-4y=8$

Step-by-step explanation:

The equation of the line in point slope form is

$y-y1=m(x-x1)$

we have

$y-1=(1/4)(x-12)$

so

$m=1/4$

$(12, 1)$

step 2

Find the equation of the line in standard form

The equation of the line in standard form is

$Ax+By=C$

where

A is positive integer

B and C are integers

we have

$y-1=(1/4)(x-12)$

Multiply by 4 both sides to remove the fraction

$4y-4=(x-12)$

$x-4y=12-4\\x-4y=8$

Answer 2

Answer:

x – 4y = 8

Step-by-step explanation:

I just took the quiz :) and got 1000000000000000000000000%