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Damm [24]
1 year ago
9

Shannon rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 13.

Mathematics
1 answer:
Bingel [31]1 year ago
4 0

Answer:

0.

Step-by-step explanation:

Fair dice are dice that have 6 sides, and the probability of rolling a side is the same as rolling another.

Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.

Hope this helps!

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7, 16, 25, 34, 43, ..... nth term is
vladimir2022 [97]

Answer:

79 is the ninth term.

Step-by-step explanation:

You add nine to each one.

7, 16, 25, 34, 43, 52, 61, 70, 79

79 is the ninth term.

6 0
2 years ago
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Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11 . (1 point)
Feliz [49]

Answer:-9√(11)

Step-by-step explanation:

5√(11) - 12√(11) - 2√(11)

Since they are all alike,as in they possess √(11),we can just add or subtract them through

-7√(11) - 2√(11)

-9√(11)

3 0
1 year ago
Solve 7x- c= k for x. <br>A. X = 7(k+C) <br>B. x = 7(K-C) <br>C. X = k+c/7 <br>D. X= k-c/7​
antoniya [11.8K]

Answer:

C

Step-by-step explanation:

you add c to both side which will then make it 7x=k+c then you would divide 7 from both sides leaving you with x=k+c/7. Except 7 will be under the k and c.

7 0
1 year ago
Evaluate the integral. ∫50∫25−x2√−25−x2√∫25−x2−z2√−25−x2−z2√1(x2+y2+z2)1/2dydzdx∫05∫−25−x225−x2∫−25−x2−z225−x2−z21(x2+y2+z2)1/2d
Kipish [7]
Is that a valid question?
4 0
2 years ago
1. Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1,
zzz [600]

Answer:


Step-by-step explanation:

Given that Miguel is playing a game

The box contains 4 chips, 2 with number 1, and other two differntly numbered as 3 and 5.

OUt of these 4, 2 chips are drawn

P(drawing same number) = 2C2/4C2 =\frac{1}{6}

Prob (drawing differnt numbers) = 1-1/6 =\frac{5}{6}

Hence prob of winning 2 dollars = \frac{1}{6}

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= \frac{1}{6}2+\frac{5}{6}(-1)=-\frac{1}{2}

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d) If it is to be a fair game expected value =0

i.e. let the amount assigned be s

Then \frac{1}{6}s-\frac{5}{6}=0\\s=5

6 0
1 year ago
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