All categories

2 years ago

Please help me answer these questions

Mathematics

1 answer:

AfilCa [17]2 years ago

6 0

(a) (3a⁴)³ = 3³a³*⁴ = 9a^12
(b) (2m³)⁶ = 2⁶m⁶*³ = 64m^18
(c) (7p⁵)² = 7²p²*⁵ = 49p^10
(d) (10k²)⁴ = 10⁴k⁴*² = 10000k⁸
(e) (5t^11)³ = 5³t^11*³ = 125t³³
(f) (x³y²)⁵ = x⁵*³y⁵*² = x^15y^10
(g)(m⁴n⁶)³ = m³*⁴n³*⁶ = m^12n^18
(h) (p⁷q³)⁴ = p⁴*⁷q⁴*³ = p²⁸q^12
(i) (a⁴b^10)² = a²*⁴b²*^10 = a⁸b^20
(j) (2x⁵y²)³ = 2³x³*⁵y³*² = 8x^15y⁶
(k) (3x⁷y⁴)³ = 3³x³*⁷y³*⁴ =27x^21y^12
(l) (5p²q⁴)³ = 5³p³*²q³*⁴ =125p⁶q^12

You might be interested in

Someone know this please help geometry if you are good at it

polet [3.4K]

Answer:

Option A) outside

$----------$

hope it helps..

have a great day!!!

3 0

1 year ago

Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot.

stiks02 [169]

Answer:

Nolan correctly identified the square numbers before and after 18.

The square roots of them are 4 and 5.

Clearly, square root of 18 should lie between 4 and 5 only.

He, then carefully squared 4.1, 4.2, 4.3 etc. and identified that 4.3 squared is nearer to 18.

Since, Nolan is finding estimated square root, his steps are cool and he didn't make any error.

4 0

2 years ago

Read 2 more answers

The path traveled by a bottlenose dolphin as it jumps out of water is modeled by the equation y = −0.4x2 + 3x, where y is the he

Tamiku [17]

Answer:

5 feet

Step-by-step explanation:

The path traveled by a bottlenose dolphin as it jumps out of water is modeled by the equation,

$y=-0.4x^2+3x$

where y is the height above water and x is the horizontal distance in feet.

If a beam of light is shone upward at an angle modeled by the equation

$x+y=10$

A beam of light hit the dolphin.

So, line must be intersect path of dolphin.

Using substation method,

Substitute y=10-x into dolphin equation.

$10-x=-0.4x^2+3x$

$-0.4x^2+4x-10=0$

$x=\dfrac{-4\pm\sqrt{4^2-4(-10)(-0.4)}}{2(-0.4)}$

$x=5\text{ feet }$

$y=5\text{ feet }$

Hence, The beam hit dolphin at 5 feet.

8 0

2 years ago

Perform the indicated operation. (y4 - 1) ÷ (y + 1)

Valentin [98]

$The\ domain:\\D:y\neq-1\\\\(y^4-1)\div(y+1)=\dfrac{(y^2)^2-1^2}{y+1}=\dfrac{(y^2-1)(y^2+1)}{y+1}\\\\=\dfrac{(y-1)(y+1)(y^2+1)}{y+1}=(y+1)(y^2+1)=y^3+y^2+y+1\\\\Used:\\(a^n)^m=a^{nm}\\\\a^2-b^2=(a-b)(a+b)$

7 0

2 years ago

Read 2 more answers

Estimate 58% of 121 by using 10%

kvv77 [185]

58% is about equal to 60%, 10% of 121 is 12.1.
12.1 * 6 = 72.6
To take this further, 58% is 2% less than 60%, or 2 times 1%. 1% of 121 is 1.21.
72.6 - (1.21 * 2) = 72.6 - 2.42 = 70.18

5 0

2 years ago