Please help me answer these questions
1 answer:
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Answer:
a) distance halfway = 16.49 [m], displacement halfway = 10.5 [m]
b) distrance traveled increases when the child completes one circuit of the track.
Step-by-step explanation:
a) Distance is a scalar quantity that tells you how much space a body has covered when moving. Displacement is a vector quantity that tells you how far from its initial position and object is after moving.
In this case, the child goes around the track only halfway from point 1 to point 2. We know the circunference or perimeter of a circle to be 2*PI*radius. We also know the child only when halfway, so we need to divide the perimeter by 2, thus we get distance = PI*radius
- distance halfway = (PI)*(5.25) = 16.49 [m]
And now that we know the definition of displacement, we can easily see that the child went from point 1 to point 2 which is located at a distance of 1 diameter from point 1:
- displacement halfway = D = 2*radius = 2(5.25) = 10.5 [m]
b)What happens to the distance when the child completes one circuit? The distance will increase beause he is now completing the circuit so he is covering more ground in his movement:
- distance circuit = 2*(PI)*radius = 2(PI)(5.25) = 32.99 [m]
32.99 is more than 16.49 so we are certain that the distance increases.
The increase of the radius is a linear increase since we have the constant rate of 0.07 inches per second
The equation for a linear growth/decay is given by the form
where 
is the rate of increase and 
is the value of 
when 
We have
when 
So the equation is
The length of the radius when
seconds is
inches
The equation for a linear growth/decay is given by the form
We have
So the equation is
The length of the radius when