All categories

2 years ago

Perform the indicated operation. (y4 - 1) ÷ (y + 1)

2 answers:

7 0

$The\ domain:\\D:y\neq-1\\\\(y^4-1)\div(y+1)=\dfrac{(y^2)^2-1^2}{y+1}=\dfrac{(y^2-1)(y^2+1)}{y+1}\\\\=\dfrac{(y-1)(y+1)(y^2+1)}{y+1}=(y+1)(y^2+1)=y^3+y^2+y+1\\\\Used:\\(a^n)^m=a^{nm}\\\\a^2-b^2=(a-b)(a+b)$

Dmitry_Shevchenko [17]2 years ago

3 0

Answer: y^3 - y^2 + y - 1

Step-by-step explanation: Factor the numerator and denominator and cancel the common factors. This should leave you with y^3-y^2+y-1.

You might be interested in

Ana played 555 rounds of golf, and her lowest score was an 808080.

laiz [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

1. Which situation does NOT represent a functional relationship?

Alex

Answer:

1. D
2. C

Step-by-step explanation:

1. .....................................................................................................

A. This is a functional relationship as the number of workers depend on the number of job sites.

y = 5x

B. This is a functional relationship as the amount of money is dependent on the number of withdrawals

y = 2500 - 200x

C. This is a functional relationship as the number of vitamins depend on the number of monkeys

y = 3x

D. This is NOT a functional relationship as the output is a fixed value. The performance and scoring may repeat.

2. .....................................................................................................

<h3>Given</h3>

A = 62x -100
B = 2x - 3

<h3>Solution</h3>

A/B =
(62x - 100)/(2x - 3) =
(31*2x - 31*3 - 7)/(2x - 3) =
(31(2x - 3) -7)/(2x - 3) =
31 - 7/(2x - 3)

Correct option is C.

7 0

2 years ago

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess

statuscvo [17]

Let's start by visualising this concept.

Number of grains on square:
1 2 4 8 16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
$T_n = ar^{n - 1}$
$T_{15} = 2^{14} = 16384$

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
$S_n = \frac{a(r^{n} - 1)}{r - 1}$
$S_{15} = \frac{2^{15} - 1}{2 - 1}$
$S_{15} = 2^{15} - 1 = 32767$

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.

6 0

2 years ago

Read 2 more answers

A share of stock in the Lofty Cheese Company is quoted at 251/4. Suppose you hold 30 shares of that stock, which you bought at 2

inn [45]

You'll make a profit of $150.

3 0

2 years ago

Mike earns $6.50 per hour plus 4% of his sales enter an equation for mikes total earnings, e, when he works x hours and has a to

Cerrena [4.2K]

First identify what each variable means. since X is the amount of hours he works, and he makes $6.50 an hour, you know you need to multiply those two numbers together creating the 6.50x. You also know Y is his total sales, and he earns 4% of Y. To find 4% of Y you need to turn the percent into a decimal, and to do this you move the decimal two spaces to the left. Since 4 is a whole number, the decimal is after the 4 so you get .04 as your decimal. Then youd multiply .04 by Y getting .04y. Lastly you add 6.50x + .04y to get E, mikes total earnings. So your final equation is

6.50x + .04y = e

Hope this all makes sense

3 0

2 years ago

Read 2 more answers