Answer:
Let a be the first term.
The sum is a1−r=33.25.
The second term is ar=7.98, so a=7.98/r.
Putting these together, 7.98/r(1−r)=33.25 or r(1−r)=0.24=0.6×0.4.
If the answer doesn't jump out at you from there, you could solve for r with the quadratic formula.
Step-by-step explanation:
I Hope It's Helpful :)
The probability p of an orangecandy is 0.2. The sample size = 100.
The mean is given by:

The standard deviation is given by:

The answers are: Mean = 20. Standard deviation = 4.
Answer:
a. $60
Step-by-step explanation:
We will use simple interest formula to solve our given problem.
, where
A= Amount after t years.
P= Principal amount.
r= Interest rate in decimal form.
t= Time in years.
Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.
As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

12 months = 1 year.




Now let us find amount repayable after 12 months for borrowing $1000.




Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.





Now let us find difference between both repayable loan amounts.


Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.
Answer with Step-by-step explanation:
We are given that
A and B are matrix.
A.We know that for two square matrix A and B
Then, 
Therefore, it is true.
B. det A is the product of diagonal entries in A.
It is not true for all matrix.It is true for upper triangular matrix.
Hence, it is false.
C.

When is a factor of the characteristics polynomial of A then -5 is an eigenvalue of A not 5.
Hence, it is false.
D.An elementary row operation on A does not change the determinant.
It is true because when an elementary operation applied then the value of matrix A does not change.
Since 1cm represents 4 meters then .5cm would represent 2 meters.