Given parameters:
Bearing of the tree from the house = 295°
Unknown:
Bearing of the house from the tree = ?
Solution:
This is whole circle bearing problem(wcb). There are different ways of representing directions from one place to another. In whole circle bearing, the value of the bearing varies from 0° to 360° in the clockwise direction.
To find the back bearing in this regard, simple deduct the forward bearing from 360°;
Backward bearing = 360° -295°
= 65°
The bearing from house to the tree is 65°
By definition, the average rate of change is given by:
We evaluate each of the functions in the given interval.
We have then:
For f (x) = x ^ 2 + 3x:
Evaluating for x = -2:
Evaluating for x = 3:
Then, the AVR is:
For f (x) = 3x - 8:
Evaluating for x =4:
Evaluating for x = 5:
Then, the AVR is:
For f (x) = x ^ 2 - 2x:
Evaluating for x = -3:
Evaluating for x = 4:
Then, the AVR is:
For f (x) = x ^ 2 - 5:
Evaluating for x = -1:
Evaluating for x = 1:
Then, the AVR is:
Answer:
from the greatest to the least value based on the average rate of change in the specified interval:
f(x) = x^2 + 3x interval: [-2, 3]
f(x) = 3x - 8 interval: [4, 5]
f(x) = x^2 - 5 interval: [-1, 1]
f(x) = x^2 - 2x interval: [-3, 4]
First, determine the center of the circle by getting the midpoint of the points given for the circumference.
midpoint = ((0 + 0)/2, (3 + -4)/2)
midpoint (0, -0.5)
Then, we get the radius by determining the distance from either of the circumferential point to the center.
radius = √(0 - 0)² + (3 +4)² = 7
The equation for the circle would be,
x² + (y + 0.5)² = 7²
Answer:
0.
Step-by-step explanation:
Fair dice are dice that have 6 sides, and the probability of rolling a side is the same as rolling another.
Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.
Hope this helps!
