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2 years ago

W = 3x + 7y solve for y

Mathematics

1 answer:

mario62 [17]2 years ago

8 0

Answer:

The value of the equation $y=\frac{W-3x}{7}$ .

Step-by-step explanation:

Consider the provided equation.

$W = 3x + 7y$

We need to solve the provided equation for y.

Subtract 3x from both side.

$W-3x= 3x-3x+ 7y$

$W-3x=7y$

Divide both sides by 7.

$\frac{7y}{7}=\frac{W-3x}{7}$

$y=\frac{W-3x}{7}$

Hence, the value of the equation is $y=\frac{W-3x}{7}$ .

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Decrease £19064.67 by 9.5% Give your answer rounded to 2 DP.

Advocard [28]

Answer:

£17253.53 to the nearest hundredth.

Step-by-step explanation:

Decreasing by 9,5% is equivalent to multiplying by 1 - 0.095 = 0.905.

19064.67 * 0.905

= £17253.52635.

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2 years ago

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: adam and melissa went fly-fishing and caught a total of 32 salmon. melissa caught three times as many salmon as adam. how many

nadya68 [22]

A=Adam
m= Melissa

a+m = 32
m= 3a
Then 3a + a = 32 or 4a =32 then a = 8

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1 year ago

The table shows how an elevator 500 feet above the ground is descending at a steady rate.

Snezhnost [94]

We are given that the elevator is descending, so the coefficient of t must be negative. The elevator's initial position is 500 feet above the ground, so this is a positive value of +500. Therefore the only choice that fits these is h(t) = -5t + 500.

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1 year ago

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A trapezoid has a base of 4.5 inches, a height of 6 inches, and an area of 21 square inches. The equation below can be used to d

Troyanec [42]

Answer:

$b_2 = -2.5$

Step-by-step explanation:

Given

$\frac{1}{2}(4.5 + b_2) * 6 = 21$

Required

Determine the value of T

$\frac{1}{2}(4.5 + b_2) * 6 = 21$

Multiply both sides by 2

$2 * \frac{1}{2}(4.5 + b_2) * 6 = 21 * 2$

$(4.5 + b_2) * 6 = 42$

Divide through by 6

$4.5 + b_2 = 42/6``$

$4.5 + b_2 = 7$

$b_2 = 7 - 4.5$

$b_2 = -2.5$

6 0

2 years ago

A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st

Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample credit hours per quarter = 15.2 credit hours

s = sample standard deviation = 2.3 credit hours

n = sample of students = 250

$\mu$ = population mean credit hours per quarter

Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < $t_2_4_9$ < 1.96) = 0.95 {As the critical value of t at 249 degree of

freedom are -1.96 & 1.96 with P = 2.5%}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $15.2-1.96 \times {\frac{2.3}{\sqrt{250} } }$ , $15.2+1.96 \times {\frac{2.3}{\sqrt{250} } }$ ]

= [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.

8 0

1 year ago