Answer: a) Length of wire to replace old one=9ft
b) Length of wire=3.09ft
Leftover wire=0.91ft
Step-by-step explanation: from the right angle triangle, Tan&=20/15
&=53.13°
Length of wire,x=cos 31.13=x/15
15cos31.13
X=9
b) Tan&=10/6
Tan^-110/6
&=59.05
Length= 6cos59.04
X=3.09
4-3.09=.91= leftover wire
In 1944 Elion joined the Burroughs Wellcome Laboratories (now part of GlaxoSmithKline (a company that makes prescription medicines)). There she was first the assistant and then the colleague of Hitchings, with whom she worked for the next four decades. Elion and Hitchings developed an array (variety) of new drugs that were effective against leukemia, autoimmune disorders, urinary-tract infections, gout, malaria, and viral herpes. Their success was due primarily to their innovative (characterized by new or unique) research methods. Rather than using the trial-and-error approach used by previous pharmacologists, Elion and Hitchings examined the difference between the biochemistry of normal human cells and that of cancer cells, bacteria, viruses, and other pathogens (disease-causing agents). They used this information to create drugs that could target a particular pathogen without harming the human host's normal cells. Their methods enabled them to eliminate much of the guesswork and wasted effort typical in previous drug research.
Answer: A
Hope this is helpful.
Step-by-step explanation:
Try to solve using simultaneous equations with each answer given.
x + 2y = 5
x = 5 - 2y
Plug this into each equation
A 2(5 - 2y) + 4y = 3
10 - 4y + 4y = 3
10 = 3 in consistent
B 5(5 - 2y) + 2y = 3
25 - 10 y + 2y = 3
25 - 8y = 3
8y = 22
y = 2.75
Using original equation solve for x
5x + 2(2.75) = 3
5x + 5.5 = 3
5x = -2.5
x = -0.5
Using original equation,
(-0.5) + 2 (2.75) = 5
-0.5 + 5.5 = 5 consistent
C 6x + 12y = 30
6(5 - 2y) + 12y = 30
30 - 12y + 12 y = 30 consistent for every value of y
D 3(5 - 2y) + 4y = 8
15 - 6y + 4y = 8
- 2y = -7
y = 3.5
x = 5 - 2y
x = 5 - 7
x = -2
Solving for x
3(-2) + 4(3.5) = -6 + 14 = 8 consistent
So A is the correct answer
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5