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2 years ago

7

At the end of the business day, Sam attempts to balance the register. According to Sam's count, the register has $1,453.27. Howe

ver, the register receipts show that the register should have $1,455.32. How much is Sam's figure off by?

2 answers:

Harlamova29_29 [7]2 years ago

5 0

$2.05 i hope this helps

Alex787 [66]2 years ago

3 0

All u need to do is subtract the bigger number from the smaller one

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If ray NP bisects <MNQ, m<MNQ=(8x+12)°, m<PNQ=78°, and m<RNM=(3y-9)°, find the value of x and y

aksik [14]

Step 1

<u>Find the measure of angle x</u>

we know that

If ray NP bisects <MNQ

then

m<MNQ=m<PNM+m<PNQ ------> equation A

and

m<PNM=m<PNQ -------> equation B

we have that

m<MNQ=(8x+12)°

m<PNQ=78°

so

substitute in equation A

(8x+12)=78+78-------> 8x+12=156------> 8x=156-12

8x=144------> x=18°

Step 2

<u>Find the measure of angle y</u>

we have

m<PNM=(3y-9)°

m<PNM=78°

so

3y-9=78------> 3y=87------> y=29°

therefore

<u>the answer is</u>

the measure of x is 18° and the measure of y is 29°

7 0

2 years ago

What is 15 tens - 1 gross

vampirchik [111]

Answer:

see the explanation

Step-by-step explanation:

we know that

A gross is equal to 120 ones or ten dozen

what is 15 tens - 1 gross

we know that

15 tens means ----> That you are adding 10, 15 times or multiplying 10 by 15, which gives you

$10(15)=150$

1 gross means ---> That you are adding 10, 12 times or multiplying 10 by 12

which gives you

$10(12)=120$

so

The algebraic expression of 15 tens - 1 gross is equal to

$150-120=30$

Convert to word expression

3 tens

8 0

1 year ago

Helpmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

alexandr402 [8]

Answer:

B. 1.2×10^-3 mm

Step-by-step explanation:

What constitutes an "appropriate" unit depends on the use of the number. Since we're not told of any particular use, we might choose the smallest of the available units: mm.

1.2×10^-3 mm

_____

<em>Additional comment</em>

The most appropriate unit would be the one that eliminates the power-of-ten multiplier:

= 1.2 µm

6 0

2 years ago

Make w the subject of the formula y-aw=2w-1

kipiarov [429]

Answer: <span>w = [ y + 1] / [a + 2]

Solution step by step:
</span>
1) given <span>formula: y-aw=2w-1

2) transpose aw and - 1

2w + aw = y + 1

3) common factor w:

w (a + 2) = y + 1

4) divide both sides by (a + 2):

w = [ y + 1] / [a + 2]
</span>

6 0

2 years ago

Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not

tangare [24]

Answer:

a.

$\bar p_1=0.05\\\bar p_2=0.067$

b-Check illustration below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let $p_1 \& p_2$ denote processes 1 & 2.

For $p_1$ : T1=10,n1=200

For $p_2$ :T2=20,n2=300

Therefore

$\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067$

b. To test for hypothesis:-

i.

$H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05$

ii.For a two sample Proportion test

$Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\$

iii. for $\frac{\alpha}{2}=(-1.96,+1.96)$ (0.5 alpha IS 0.025),

reject $H_o$ if $|Z|>1.96$

iv. Do not reject $H_o$ . The noncomforting proportions are not significantly different as calculated below:

$z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}$

z=-0.78

c. $(1-\alpha).100\%$ for the p1-p2 is given as:

$(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645 \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\$

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0

2 years ago