Answer:
0.7673
Step-by-step explanation:
We have the following:
The null and alternative hypothesis is,
H0: m = 290
Ha: m> 290
x = 285.2
m = 290
sd = 59.3
n = 82
is m the mean, sd the standard deviation and n the population size
Now we calculate the value of z like this:
z = (x - m) / sd / (n ^ (1/2))
z = (285.2 - 290) / 59.3 / (82 ^ (1/2))
z = -0.73
now
P (z> -0.73) = 1 - P (z <-0.73)
we look at the normal distribution table
P = 1 - 0.2327 = 0.7673
Therefore the value of p is equal to 0.7673
Answer:
24.2(to the nearest tenth)
Step-by-step explanation:
The question is ungrouped data type
standard deviation =√ [∑ (x-μ)² / n]
mean (μ)=∑x/n
=
=33.3
x-μ for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be
-28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7
(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49
∑ (x-μ)² will be = 7028.59
standard deviation = √(7028.59 / 12)
=24.2
Answer:
a) The continuous rate of growth of this bacterium population is 45%
b) Initial population of culture at t = 0 is 950 bacteria
c) number of bacterial culture contain at t = 5 is 9013 bacteria
Step-by-step explanation:
The number of bacteria in a culture is given by
n(t) = 950
a) rate of growth is
Bacteria growth model N(t) = no
Where r is the growth rate
hence r = 0.45
= 45%
b) Initial population of culture at t = 0
n(0) = 950
= 950
= 950 bacteria
c) number of bacterial culture contain at t = 5
n(5) = 950
= 950
= 9013.35
= 9013 bacteria