-3x-2.5=y would be an equivalent to that equation
Answer:
The population that gives the maximum sustainable yield is 45000 swordfishes.
The maximum sustainable yield is 202500 swordfishes.
Step-by-step explanation:
Let be
, the maximum sustainable yield can be found by using first and second derivatives of the given function: (First and Second Derivative Tests)
First Derivative Test

Let equalize the resulting expression to zero and solve afterwards:


Second Derivative Test

This means that result on previous part leads to an absolute maximum.
The population that gives the maximum sustainable yield is 45000 swordfishes.
The maximum sustainable yield is:


The maximum sustainable yield is 202500 swordfishes.
Answer:
Step-by-step explanation:
Given the following :
Number of shares purchased (2016) = 50
Purchase price of shares $396.33 per share
Closing price per share four years later = $778.38
A) What did Chadwick pay for all of the shares in 2016?
Purchase price per share × number of shares.
$396.33 × 50 = $19,816.50
B) What was the closing value of all of the shares four years later?
Closing price per share × number of ahaf
=$778.38 × 50
= $38,919
C.) Profit on stock :
$(38,919 - 19,816.50)
= $19,102.5
D) What is his rate of return on his shares when he sold them?
(Current Purchase - initial value) /current price
(778.3 - 396.33) / 396.33
= (381.97 / 396.33) 100%
= 0.9637675
=
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.
For this case, the first thing we are going to do is rewrite the function.
We have then:
h (x) = 505.5 + 8 * exp (-0.9 * x)
We evaluate the value of x = 5 in the function.
We have then:
h (5) = 505.5 + 8 * exp (-0.9 * 5)
h (5) = 505.588872
round to the nearest tenth:
h (5) = 505.6
Answer:
the value of h (5) is:
h (5) = 505.6