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2 years ago

8

The owner of a music store received a shipment of 1532 cds came in 37 boxes. The same number of cds were in 36 of the boxes. How

many cds were in the remaining

1 answer:

AVprozaik [17]2 years ago

6 0

Answer:

20 CDs

Step-by-step explanation:

36 x 42 = 1512

1532 - 1512 = 20

The last box has 20 CDs

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Manny is making 12 quarts of orange juice from concentrate and water. The number of quarts of water is 3 times the number of qua

trasher [3.6K]

Answer: There are 3 quarts of concentrate and 9 quarts of water.

Step-by-step explanation:

Since we have given that

Ratio of number of quarts of water to number of quarts of concentrate is

3:1

Number of quarts of orange juice from concentrate and water = 12 quarts

So, the number of quarts of concentrate would be

$\dfrac{1}{4}\times 12\\\\=\dfrac{12}{4}\\\\=3\ quarts$

the number of quarts of water would be

$\dfrac{3}{4}\times 12\\\\=3\times 3\\\\=9\ quarts$

Hence, there are 3 quarts of concentrate and 9 quarts of water.

8 0

2 years ago

Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val

Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

$A(t) = Pe^{rt}$

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that $P = 330$

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

$A(t) = Pe^{rt}$

$590 = 330e^{8r}$

$e^{8r} = \frac{590}{330}$

$e^{8r} = 1.79$

Applying ln to both sides:

$\ln{e^{8r}} = \ln{1.79}$

$8r = \ln{1.79}$

$r = \frac{\ln{1.79}}{8}$

$r = 0.0726$

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

$A(t) = 330e^{0.0726t}$

$A(10) = 330e^{0.0726*10} = 682$

The value of the account in the year 2009 will be $682.

4 0

2 years ago

Triangle J K L is shown. Angle K L J is a right angle. The length of hypotenuse K J is 10.9 centimeters and the length of L J is

scZoUnD [109]

Answer:

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

Step-by-step explanation:

From the given triangle JKL;

Hypotenuse KJ = 10.9

Length LJ is the opposite = 8.9cm

The angle LKJ is the angle opposite to side KJ = x

Using the SOH CAH TOA Identity;

sin theta = opp/hyp

sin LKJ = LJ/KJ

Sinx = 8.9/10.9

x = arcsin(8.9/10.9)

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

7 0

2 years ago

Read 2 more answers

E varies directly with the square root of C. If E=40 when C=25, find: C when E = 10.4

sukhopar [10]

Answer: C = 1.69

Step-by-step explanation:

E is proportional to √C

To remove proportionality, introduce a constant (k).

E = k × √C

From question,

E = 40 and C = 25

So,

40 = k ×√25

40 = k × 5

k = 8

Now,

C = ?

E = 10.4

k = 8

E = k × √C

10.4 = 8 × √C

10.4 / 8 = √C

( 10.4 / 8 ) ^ 2 = C

C = 1.69

6 0

2 years ago

Read 2 more answers

Find the value of x RT=4x+10 SW= 5x-20

Liula [17]

Well, as you can see from the rectangle RT and SW should have equal lengths. So to find the value of x, we need to do.....

4x + 10 = 5x - 20
-x + 10 = -20 (Subtraction property of equality)
-x = -30 (Subtraction property of equality)
x = 30 (Division property of equality)

To check our work:

4(30)+10 = 130
5(30)-20 = 130

So, the value of x is 30!

5 0

2 years ago