Answer:
The farmer needs 24 crates to hold the carrots.
Step-by-step explanation:
To determine how many crates the farmer needs to hold the carrots, knowing that his farm has 4.8 acres of land, where he can harvest 120 pounds per acre, and that each crates can hold up to 24 pounds of carrots, the following calculation must be performed:
(4.8 x 120) / 24 = X
576/24 = X
24 = X
Thus, the farmer needs 24 crates to hold the carrots.
Answer: Daniel bought 3 apples and 7 bananas.
Step-by-step explanation:
Let x represent the number of apples that Daniel bought.
Let y represent the number of bananas that Daniel bought.
He bought a total of 10 apples and bananas altogether. This means that
x + y = 10
Daniel and his children went into a grocery store and he bought $10.15 worth of apples and bananas. Each apple costs $1.75 and each banana costs $0.70. This means that
1.75x + 0.7y = 10.15 - - - - - - - - - - - 1
Substituting x = 10 - y into equation 1, it becomes
1.75(10 - y) + 0.7y = 10.15
17.5 - 1.75y + 0.7y = 10.15
- 1.75y + 0.7y = 10.15 - 17.5
- 1.05y = - 7.35
y = - 7.35/- 1.05
y = 7
x = 10 - y = 10 - 7
x = 3
Answer:
The ultra-marathon Idita Rod Trail is about 38 times longer than the Boston Marathon.
Step-by-step explanation:
Let
x -----> the length of the Boston Marathon in meters
y -----> the length of the Idita rod Trail Invitational ultra-marathon in meters
we have


we know that
To find out how many times as long is the course of the Idita rod Trail ultra-marathon as that of the Boston Marathon, divide the length of the Idita rod Trail Invitational ultra-marathon by the length of the Boston Marathon
so


Remember that
To divide two numbers in scientific notation, divide their coefficients and subtract their exponents

therefore
The ultra-marathon Idita Rod Trail is about 38 times longer than the Boston Marathon.
%62.5 you divide the amount of males with the total amount of guests then you will get 0.625 so you put the comma two places behind and add a percentage.
Answer
given,
thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
X = U[0.95,1.05] 0.95≤ x ≤ 1.05
the cumulative distribution function of flange
F(x) = P{X≤ x}=
=
b) P(X>1.02)= 1 - P(X≤1.02)
= 
= 0.3
c) The thickness greater than 0.96 exceeded by 90% of the flanges.
d) mean = 
= 1
variance = 
= 0.000833