Answer:
2.6
Step-by-step explanation:
just put one part of the equation in y1 and the other in y2 and hit 2nd trace 5 an hit enter 4 times
then it will bring a graph hit enter 3 time again and it will show u the answer at the bottom left
Answer: 2.76 g
Step-by-step explanation:
The formula to find the standard deviation:-
The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.
Then, 
Now, 
Then, 
Hence, the standard deviation of his measurements = 2.76 g
Divide the APR by 360 days and multiply it by 30 days to get the monthly interest. Each loan is usually secured by the car you bought. So we will use the secured APR.
8. Average rating secured apr: 5.85% divide by 360 multiply by 30: 0.4875% monthly rate
Cost of car: 19,725 ; sales tax: 4.75% ; down payment: 2,175
19,725 x 1.0475 = 20,661.94 - 2,175 = 18,486.94 loan amount
18,486.94 x 0.4875% = 90.12 accrued interest for the 1st month.
9. Excellent rating secured apr: 4.80% divide by 360 multiply by 30: 0.40% monthly rate
Cost of car: 15,867 ; sales tax: 5.25% ; down payment: 10% of total cost
15,867 x 1.0525 = 16,700.02 x 90% = 15,030.02 the principal balance at the start of the loan.
10. Fair rating secured apr: 7% divide by 360 multiply by 30: 0.5833% monthly rate
Cost of new car: 19,072 ; sales tax: 4.5% ; down payment: 1,200
Cost of used car: 15,365; sales tax: 4.5% ; down payment: 1,200
19,072 x 1.045 = 19,930.24 - 1,200 = 18,730.24
18,730.24 x 0.5833% = 109.25 accrued interest
15,365 x 1.045 = 16,056.43 - 1,200 = 14,856.43
14,856.43 x 0.5833% = 86.66 accrued interest
109.25 - 86.66 = 22.59 is the difference in interest accrued by the end of the first month.
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.
