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Alchen [17]
2 years ago
8

A building casts a shadow 25 m long. At the same time, the shadow cast by a 44-cm tall pole is 59 cm long. Find the height of th

e building.
 A. 17.1 m B. 32.0 m C. 33.5 m D. 18.6 m
Mathematics
1 answer:
EastWind [94]2 years ago
3 0

For this, we are going to be using proportions to solve. But firstly, we have to convert cm to m. For this, I'll be using dimensional analysis:

\frac{44\ cm}{1}*\frac{0.01\ m}{1\ cm}=\frac{0.44}{1}=0.44\ m

\frac{59\ cm}{1}*\frac{0.01\ m}{1\ cm}=\frac{0.59}{1}=0.59\ m

Now that we have everything in meters, we can put it into proportions. In this case, our proportion is \frac{x}{25} =\frac{0.44}{0.59}

Firstly, cross-multiply: 0.59x=11

Next, divide both sides by 0.59, and your answer will be x = 18.6 m, or D.

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insens350 [35]

The question is missing the figure. So, the figure is attached below.

Answer:

C. 350 m

Step-by-step explanation:

Given:

Scale  is given as:

1 unit  : 25 meters

This means that 1 unit on the grid is equivalent to 25 meters in actual.

Now, from the figure, the horizontal distance across the park is 14 units.

1 unit = 25 meter

Now, we can find the actual distance using unitary method and thus multiplying 25 and 14 to get the actual distance across the park horizontally.

∴ 14 units = 25\times 14=350 meters.

Therefore, the horizontal distance across the park is 350 m in actual.

So, the correct option is option C.

7 0
1 year ago
"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

4 0
1 year ago
How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?
Mrac [35]
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8} 
{2} U {1, 5, 6, 8} 
{5} U {1, 2, 6, 8} 
{6} U {1, 2, 5, 8} 
{8} U {1, 2, 5, 6} 
{1, 2} U {5, 6, 8} 
{1, 5} U {2, 6, 8} 
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6} 
{1, 2, 5} U {6, 8} 
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5} 
The answer is 15 distinct pairs of disjoint non-empty subsets.
5 0
1 year ago
The box-and-whisker plot below shows the age distribution of people at a family reunion. A box-and-whisker plot is shown. The nu
Setler79 [48]

Answer:

The answer is C

Step-by-step explanation:

got it right on edge

5 0
2 years ago
Read 2 more answers
Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot
kogti [31]

Answer:

x=\frac{30}{7}

Step-by-step explanation:

We have been given an equation \frac{2}{3}x=-\frac{1}{2}x+5. We are asked to solve our given equation.

First of all, we will add \frac{1}{2}x on both sides of equation to separate x variable on one side of equation.

\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5

\frac{2}{3}x+\frac{1}{2}x=5

Now, we will make a common denominator.

\frac{2*2}{3*2}x+\frac{1*3}{2*3}x=5

\frac{4}{6}x+\frac{3}{6}x=5

Add numerators:

\frac{4+3}{6}x=5

\frac{7}{6}x=5

Upon multiply both sides of our equation by \frac{6}{7}, we will get:

\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}

x=\frac{5*6}{7}

x=\frac{30}{7}

Therefore, the solution for our given equation is x=\frac{30}{7}.

5 0
1 year ago
Read 2 more answers
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