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2 years ago

The box plot shows the number of cousins students in Mr. Myers class have. Which statement about the data must be true

Mathematics

2 answers:

lana [24]2 years ago

8 0

Answer: The answer is C

nikitadnepr [17]2 years ago

7 0

Answer:

We choose C

The spread from the lower quartile to the median is greater than the spread from the median to the upper quartile.

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

Please have a look at the attached photo

My answer:

Given the information in the photo, we can know that:

Median: 7

Upper quartile: 9
Lower quartile: 4
Interquartile range: 9 - 4 = 5
Lower quartile to median: 7 - 4 = 3
Upper quartile to median: 9 - 7 = 2

Let analyse 4 answers:

A. Wrong, Lower quartile to median is more than Uper quartile to median

B. Wrong

C. True

D. Wrong

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The number 31 is increased to 44. What is the percentage by which the number was increased, to the nearest tenth of a percent?

Sophie [7]

Answer:

41.9 %

Step-by-step explanation:

when you look at the to numbers you will see that the two has a 41.9 % difference.

3 0

1 year ago

Eighty-five more than the square of a number is the same as the square of the quantity that is $17$ less than the number. What i

Usimov [2.4K]

To solve that we first need to write it as an equation where x is the number:
85 + x^2 = (x-17)^2
85 + x^2 = x^2 - 34x + 289
Now organize the equation by gathering like terms in the same side lf the equation:
You can shift 85 to the other side by subtracting 85 from both sides of the equation:

85 - 85 + x^2 =x^2 34x +289 - 85
x^2 =x^2 + 34x +204

And shift x^2 to the other side by subtracting x^2 from both sides:
x^2 - x^2 =x^2 -x^2 + 34x +204
0 = 34x + 204

Shift 34x to the other side by subtracting 34x from sides
-34x = 34x - 34x + 204
-34x = 204

And now isolate x by dividing both sides of the equation by -34
-34/-34x = 204/-34
x = -6
Thats your awnser , the number is -6
I hope you understood my brief explanation...

5 0

1 year ago

Person A buys 10 granola bars and 6 cups of yogurt for 518 Person B buys 5 granola bars and 4 cups of yogurt for $9.50. Find the

Alja [10]

Person A buys 10 granola bars and 6 cups of yogurt for $18

Person B buys 5 granola bars and 4 cups of yogurt for $9.50

Let x represent the granola bars

Let y represent the yogurt

10x + 6y = 18 << ( Divide both sides by 2 )

The second equation is 5x + 4y = 9.50. Now subtract the two equations.

5x + 4y = 9.50

-5x - 3y = -9

y = $.50

5x + 3(.50) = 9

5x + 1.50 = 9

5x = 7.5

x = $1.50

I hope this answered your question

Please remember to rate my answer and comment bellow if you have any questions

4 0

1 year ago

Choose the three shapes that have an area of 36 square centimeters.

Kay [80]

Answer:

6cm

Step-by-step explanation:

Area of a square =

$s^2$

Where s = one side

s = ?

$A = s^2\\\\36 =s^2$

Square root both sides

$\sqrt{36} = \sqrt{s^2} \\\\6 =s$

5 0

1 year ago

preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha

VladimirAG [237]

Answer:

$n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79$

n=369

Step-by-step explanation:

1) Notation and definitions

$X=40$ number of the selected labourers opt for a new incentive scheme.

$n=100$ random sample taken

$\hat p=\frac{40}{100}=0.4$ estimated proportion of the selected labourers opt for a new incentive scheme.

$p$ true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: