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2 years ago

The box plot shows the number of cousins students in Mr. Myers class have. Which statement about the data must be true

Mathematics

2 answers:

lana [24]2 years ago

8 0

Answer: The answer is C

nikitadnepr [17]2 years ago

7 0

Answer:

We choose C

The spread from the lower quartile to the median is greater than the spread from the median to the upper quartile.

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

Please have a look at the attached photo

My answer:

Given the information in the photo, we can know that:

Median: 7

Upper quartile: 9
Lower quartile: 4
Interquartile range: 9 - 4 = 5
Lower quartile to median: 7 - 4 = 3
Upper quartile to median: 9 - 7 = 2

Let analyse 4 answers:

A. Wrong, Lower quartile to median is more than Uper quartile to median

B. Wrong

C. True

D. Wrong

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△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).

dmitriy555 [2]

△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).

The distance between the x-coordinates of R and T is 3 .

The distance between the y-coordinates of R and T is 6.

R' is 1 unit left,2 units up from T, so the coordinates of R' are (2,0)

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2 years ago

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You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh

lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

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2 years ago

The cost of 9 scarves is $65.25. What is the unit price?<br><br> The unit price is $____ per scarf.

Strike441 [17]

Answer:

7.25 each or 7.00 if rounded

Step-by-step explanation:

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2 years ago

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brian filled 72 glasses with apple juice for a school party if each glass holds 1 cup of juice how many quarts of apple juice di

GaryK [48]

4 cups in a quart so you would have 72 cups divided by 4 and get 18

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2 years ago

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?

KIM [24]

Answer:

The answer is

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$tan(\theta)=-1$

Step-by-step explanation:

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin^{2}(\theta)+cos^{2}(\theta)=1$

In this problem we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

$\frac{3\pi}{2}$

The angle $\theta$ belong to the third or fourth quadrant

The value of $sin(\theta)$ is negative

Step 1

Find the value of $sin(\theta)$

Remember

$sin^{2}(\theta)+cos^{2}(\theta)=1$

we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(\theta)=1-\frac{1}{2}$

$sin^{2}(\theta)=\frac{1}{2}$

$sin(\theta)=-\frac{\sqrt{2}}{2}$ ------> remember that the value is negative

Step 2

Find the value of $tan(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}$

$tan(\theta)=-1$

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2 years ago

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