1. The speed at which an automated assembly line produces a product follows a normal distribution with mean production time of 3
1 answer:
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The answer is the first choice - see picture for solution:
Answer:
Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.
Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).
Step-by-step explanation:
Part 1:
The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).
The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).
We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.
The relation between the vertices of ABCDE and MNOPQ are defined as
It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.
Part 2:
If polygon MNOPQ is translated 3 units right and 5 units down, then
Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).
Answer:
0.82 = 82% probability that at least one party will not order drinks
Step-by-step explanation:
For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.
This means that
During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?
6 parties, so n = 6.
Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So
We want P(X < 6). So
In which
0.82 = 82% probability that at least one party will not order drinks