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Lapatulllka [165]
2 years ago
5

1. The speed at which an automated assembly line produces a product follows a normal distribution with mean production time of 3

2.20 seconds and standard deviation of 1.05 seconds. A full production run from this line consists of 20 completed products. What is the probability that a full production run will take less than 32 seconds on average to produce?2. Recent homebuyers from a local developer allege that 30% of the houses this developer constructs have some major defect that will require substantial repairs. To test this allegation, we randomly sample 20 homes constructed by the developer and find that two of the homes did indeed have some major defect. If the allegation is correct, what is the probability of observing at most two defective homes out of a random sample of 20?3.It is believed that 15% of people who fly on commercial airliners are "very concerned" about the safety of the carrier they have chosen. If this is accurate, what is the probability that out of 150 randomly selected people who fly on commercial airliners, between 20 and 25 of them are "very concerned" about the safety of the carrier which they have chosen?
Mathematics
1 answer:
strojnjashka [21]2 years ago
8 0

Answer: Probability = 0.2

Step-by-step explanation:

Given data:

Mean production time = 32.20 seconds

Standard deviation = 1,05seconds

probability that a full production run will take less than 32 seconds on average to produce

= P(Xbar<32)

= P(Z<-0.8518)

= 0.2

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Complete Question

The complete qustion is shown on the first uploaded image

Answer:

The correct option is B

Step-by-step explanation:

From the question we are told that

      The sample size  is  n = 49

       The mean is  \mu  =  17ppb

       The standard deviation is \sigma =  14 ppb

Generally the standard error of this measurement is mathematically represented as

       \sigma_z  =  \frac{\sigma}{\sqrt{n} }      

substituting values

      \sigma_{\= x}  =  \frac{14}{\sqrt{49} }  

     \sigma_{\= x}  =  2ppb

Now the probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb represented as P(X < 15 )

Next is to find the z value

    z =  \frac{\mu -\sigma }{\sigma_{\= x}}

     z =  \frac{15-17}{2}

      z =  -1

Now checking the z-table for the z-score of  -1 we have  

      P(X

                       

       

     

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