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blsea [12.9K]
2 years ago
6

On a December day, the probability of snow is 0.30. The probability of a "cold" day is 0.50. The probability of snow and "cold"

weather is 0.15. Are snow and "cold" weather independent events?a only if given that it snowedb Noc Yesd only when they are also mutually exclusive
Mathematics
1 answer:
Margarita [4]2 years ago
8 0

Answer:

Yes, snow and cold weather are independent.

Step-by-step explanation:

We are given the following in the question:

C: Cold weather

S: Snow

P(C) = 0.50

P(S) =0.30

P(S\cap C) = 0.15

We have to check whether snow and cold whether are independent events.

If the events A and B are independent then,

p(A\cap B) = P(A)\times P(B)

Checking,

p(S\cap C) = P(S)\times P(C)\\0.15 = 0.30\times 0.50

Thus, the two events are independent.

For mutually exclusive events

P(A\cap B) = 0

Thus, the given events are not mutually exclusive.

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Susan is attending a talk at her son's school. There are 8 rows of 10chairs where 54 parents are sitting. Susan notices that eve
kozerog [31]

Answer:

The largest possible number of adjacent empty chairs in a single row is 3

Step-by-step explanation:

The parameters given are;

The number of chairs = 8 × 10 = 80 chairs

The number of parents = 54

Sitting arrangements of parents = Alone or to one other person

Therefore;

The maximum number of parents on a row = 1 + 1 + 0 + 1 + 1 + 0 + 1 + 1 + 0 + 1 = 7

Hence when the rows have the maximum number of parents occupying the seats we have for the 8 rows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 56

But there are only 54 parents, therefore, up to the 7th row will have 7 parents while the 8th row will have only 5 parents to make the possible sitting arrangement to be as follows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 5 = 54

The sitting arrangement for the 8th row is therefore

1 + 1 + 0 + 1 + 1 + 0 + 1 + 0 + 0 + 0

Hence there will be three empty seats in the 8th row making the largest possible number of adjacent empty chairs in a single row = 3.

4 0
2 years ago
Is the sum of the areas of two smaller squares equal to the area of a large square if the sides lengths of the squares are 8 fee
77julia77 [94]
No.
The sum of the areas of the two smaller squares is 5^2 + 3^2 = 34
The area of the larger square is 8^2=64
34 does not = 64
5 0
2 years ago
The library charged Monica $50 for a book that was 10 days overdue
barxatty [35]
Erm what’s your question?
8 0
2 years ago
Tan20+tan40+tan60.......+tan180=?
Leno4ka [110]
The answer is 0. 
assuming by the dots that it includes tan80 +tan100 +tan120 +tan140 +tan160 in the equation. 
5 0
2 years ago
Which of the following statements are true concerning the mean of the differences between two dependent samples​ (matched pairs)
elena-s [515]

Answer:

A and C

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations we can use it.  

And in order to conduct it we need to have some assumptions:

1) The dependent variable must be continuous (interval/ratio).

2) The observations are independent of one another.

3) The dependent variable should be approximately normally distributed.

4) The dependent variable should not contain any outliers.

Let's analyze one by one the options on this case:

A. The methods used to evaluate the mean of the differences between two dependent variables apply if one has 86 IQ scores of taxpayers from Texas and 86 IQ scores of taxpayers from Ohio

We can assume that is true since the two variables are dependent and we are assuming that all the other conditions are satisfied to use the t paired test.

B. The requirement of a simple random sample is satisfied if we have matched pairs of voluntary response data.

That's not neccesary true since is not a requirement in order to use the t pairedtest.

C. If one has more than 23 matched pairs of sample​ data, one can consider the sample to be large and there is no need to check for normality.

We can assume that is true since we need to ensure normality in order to apply the test and if the sample size is large enough large we can apply the test.

D. If one has twenty matched pairs of sample​ data, there is a loose requirement that the twenty differences appear to be from a normally distributed population.

False the requirement of normality is important to apply the test not a loose requirement.

E. If one wants to use a confidence interval to test the claim that mu Subscript d Baseline greater than 0 with a 0.01 significance​ level, the confidence interval should have a confidence level of 98​%.

That's not correct the significance level is \alpha=1-0.98=0.02 and that not correspond to the significance level given on this case.

7 0
1 year ago
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