1 year ago

Write each fraction as a sum of unit fractions 7/10

Mathematics

1 answer:

seropon [69]1 year ago

8 0

Answer:

3/10+4/10=7/10

Step-by-step explanation:

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What’s 4x4x2-4 in a fraction over 2

JulijaS [17]

Answer:

it should be 12/2 or 6 i believe

Step-by-step explanation:

4x4 = 8

8x2 = 16

16-4 = 12

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2 years ago

A sixth grade teacher takes students on a field trip to the beach. One student finds several pebbles that have a rounded shape a

Leto [7]

Answer:

The shape of the pebbles is a result of weathering and deposition.

Step-by-step explanation:

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2 years ago

This relationship is given by the equation, v = gt. In this equation, g is the acceleration due to gravity, t is the number of s

DENIUS [597]

v=gt,

Initial value when time t=0, v=g*0=0.

t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.

v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.

Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².

Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.

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1 year ago

The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsigh

Nesterboy [21]

Answer:

The numbers of doors that will have no blemishes will be about 6065 doors

Step-by-step explanation:

Let the number of counts by the worker of each blemishes on the door be (X)

The distribution of blemishes followed the Poisson distribution with parameter $\lambda =0.5$ / door

The probability mass function on of a poisson distribution Is:

$P(X=x) = \dfrac{e^{- \lambda } \lambda ^x}{x!}$

$P(X=x) = \dfrac{e^{- \ 0.5 }( 0.5)^ x}{x!}$

The probability that no blemishes occur is :

$P(X=0) = \dfrac{e^{- \ 0.5 }( 0.5)^ 0}{0!}$

$P(X=0) = 0.60653$

P(X=0) = 0.6065

Assume the number of paints on the door by q = 10000

Hence; the number of doors that have no blemishes is = qp

=10,000(0.6065)

= 6065

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2 years ago

How many six-digit odd numbers are possible if the leftmost digit cannot be zero

Romashka [77]

For the leftmost digit there are 9 possibilities!

4 0

2 years ago