Ask question

Ask question

All categories

2 years ago

10

You work at a fruit market. Bananas cost 50¢ a pound. A customer hands you a bunch of bananas that weighs 3 pounds. How much sho

uld you charge for the bunch of bananas?

2 answers:

weqwewe [10]2 years ago

5 0

3 pounds of bananas cost $1.50

Goshia [24]2 years ago

4 0

Answer: I should charge 150¢ for the bunch of bananas.

Step-by-step explanation: Given that I work at a fruit market and bananas cost 50¢ a pound.

A customer hands me a bunch of bananas that weighs 3 pounds.

We are to find the price that I should charge for the bunch of bananas.

We will be using the UNITARY method to solve the given problem.

Also, we know that

100 ¢ = $1.

Cost of 1 pound of bananas = 50¢

Therefore, the cost of 3 pounds of bananas is given by

p = (50 × 3)¢ = 150¢ = $1.50.

Thus, I should charge 150¢ for the bunch of bananas.

You might be interested in

Leslie has 8pencils. She has 9 fewer pencils than Michelle. How many pencils does Michelle have?

sammy [17]

Answer:

<u>Michelle has 17 pencils</u>

Step-by-step explanation:

Number of pencils Leslie has = 8 (She has 9 fewer pencils than Michelle)

Number of pencils Michelle has = 9 more than Leslie

How many pencils does Michelle have?

If Leslie has 8 and she has 9 fewer than Michelle, then:

Michelle has 9 more than Leslie

<u>Michelle has 9 + 8 = 17 pencils</u>

7 0

2 years ago

The function f(x) = 1/2 x + 3/2 is used to complete this table.

Mrac [35]

Answer:

a) f(-1/2) = -2 is NOT TRUE.

b) f(0) =3/2 is TRUE.

c) f(1) = -1 is NOT TRUE.

d) f(2) = 1 is NOT TRUE.

e) f(4) = 7/2 is TRUE.

Step-by-step explanation:

Here, the given function is $f(x) = (\frac{1}{2}) x+\frac{3}{2}$

Now, checking for each values for the given function:

a) Putting x = (-1/2):

$f(\frac{-1}{2} ) = (\frac{1}{2})(\frac{-1}{2} ) +\frac{3}{2} = \frac{-1}{4} + (\frac{3}{2} )\\\implies f(x) = \frac{-1 + 6}{4} = (\frac{5}{4} )$

and (5/4) ≠ -2

Hence, f(-1/2) = -2 is NOT TRUE.

b)Putting x = 0 :

$f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )$

Hence, f(0) =3/2 is TRUE.

c) Putting x = 1:

$f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2} = \frac{1}{2} + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2} = (\frac{4}{2} ) = 2\implies 2 \neq -1$

Hence, f(1) = -1 is NOT TRUE.

d)Putting x = 2:

$f(2 ) = (\frac{1}{2})(2 ) +\frac{3}{2} = 1+ (\frac{3}{2} )\\\implies f(x) = \frac{2 + 3}{2} = (\frac{5}{2} )$

and (5/2) ≠ 1

Hence, f(2) = 1 is NOT TRUE.

e)Putting x = 4:

$f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2} = 2 + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2} = (\frac{7}{2} )$

Hence, f(4) = 7/2 is TRUE.

4 0

2 years ago

A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-

sergiy2304 [10]

Answer:

The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

Step-by-step explanation:

The confidence interval formula for mean difference for a paired data is as follows:

$CI=\bar x_{d}\pm t_{\alpha/2, (n-1)}\times \frac{s_{d}}{\sqrt{n}}$

Here,

$\bar x_{d}$ = sample mean of the difference,

$s_{d}$ = sample standard deviation of the difference,

<em>n </em>= sample size (both samples are of same size).

$t_{\alpha/2, (n-1)}$ = critical value of <em>t</em>

(<em>n</em> - 1) = degrees of freedom

The information provided is:

<em>n</em> = 5

Confidence level = 95%

The critical value of <em>t</em> is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (5-1)}$

$=t_{0.025, 4}$

$=2.776$

*Use a <em>t</em>-table for the critical value of <em>t</em>.

Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

4 0

2 years ago

What is the volume of the pyramid?

s2008m [1.1K]

Answer:

$16\sqrt{3}$ $cm^{3}$

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo,

<em>A solid oblique pyramid has an equilateral triangle as a base with an edge length of 4StartRoot 3 EndRoot cm and an area of 12StartRoot 3 EndRoot cm2. </em>

<em>What is the volume of the pyramid?</em>

My answer:

As we know, The volume of a pyramid = $\frac{1}{3}$ base area × its height

Given:

Side lenght of the base is; $4\sqrt{3} cm$

=> The area of the base is $12\sqrt{3}$ $cm^{2}$

In Δ ACB measure of angle ACB is 90° and m∠ CAB is 30°

We use: $tan(30) = \frac{BC}{AC}$

<=> BC = $4\sqrt{3}*tan(30)$

= 4 cm

And BC is the height of the the pyramid

=> The volume of a pyramid = $\frac{1}{3}$ $12\sqrt{3}$ $cm^{2}$ * 4 cm

= $16\sqrt{3}$ $cm^{3}$

5 0

2 years ago

Read 2 more answers

Fred and George ate 23 apples in July, 46 apples in August, 69 apples in September, and 92 apples in October. If this trend cont

VARVARA [1.3K]

The answer is 115

The sequence of the total apples look like this:

23 _ 46 _ 69_92_X

In which x is the total amount of apples eaten in the october.

From the sequence above we can see that each months gred and george consume additional of 23 apples

proof:
46 - 23 = 23
69 - 46 = 23
92 - 69 = 23

So, the amount of apples they will eat in November is:
92 + 23 = 115

4 0

2 years ago