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meriva
2 years ago
10

You work at a fruit market. Bananas cost 50¢ a pound. A customer hands you a bunch of bananas that weighs 3 pounds. How much sho

uld you charge for the bunch of bananas?
Mathematics
2 answers:
weqwewe [10]2 years ago
5 0
3 pounds of bananas cost $1.50
Goshia [24]2 years ago
4 0

Answer:  I should charge 150¢ for the bunch of bananas.  

Step-by-step explanation:  Given that I work at a fruit market and bananas cost 50¢ a pound.

A customer hands me a bunch of bananas that weighs 3 pounds.

We are to find the price that I should charge for the bunch of bananas.

We will be using the UNITARY method to solve the given problem.

Also, we know that

100 ¢ = $1.

Cost of 1 pound of bananas =  50¢

Therefore, the cost of 3 pounds of bananas is given by

p = (50 × 3)¢ = 150¢ = $1.50.

Thus, I should charge 150¢ for the bunch of bananas.  

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Please help I don't understand this problem. I need to get this done by tonight.
Lapatulllka [165]

Answer:

Step-by-step explanation:

24

4 0
2 years ago
Salmon often jump waterfalls to reach their breeding grounds. One salmon starts 2.00m from a waterfall that is 0.55m tall and ju
Law Incorporation [45]

Answer: 6.2 m/s

Explanation:

1) This is a projectile motion (parabolic)

2) Velocity:

i) initial velocity = V₀

ii) Horizontal component:

V₀x = V₀ cos α

The horizontal velocity is constant, so Vx = V₀x

ii) Vertical component:

V₀y = V₀ sin α

The vertical component is linear with acceleration = g ≈ 9.8 m/s²

Vy = V₀y - gt = V₀ sin α - gt

3) Displacement equations

i) Horizontal displacment:

x = V₀ cosα t

ii) Vertical displacement:

y = V₀ sin α t - g t² / 2

y ≈ V₀ sin α t - 4.9 t²

4) Solution

i) x = V₀ cosα t = V₀ cos(32°) t = 2.00 m ← salmon starts 2.00m from a waterfall

⇒ V₀ = 2 / [cos(32°) t ]

ii) y = V₀ sin α t - 4.9 t² = V₀ sin(32°) t - 4.9 t²

iii) Replace V₀ with 2 / [cos(32°) t ]

y = sin(32°) × 2 / [cos(32°) t ] × t - 4.9t² = 2 tan(32°) - 4.9t²

iv) Use jump's height (y = 0.55m) and solve

⇒ 0.55 = 2 tan(32°) - 4.9t²

t² = [2 tan(32°) - 0.55 ] / 4.9 = 0.143 s²

⇒ t = √ (0.143s²) = 0.38 s

v) Use V₀ = 2 / [cos(32°) t ] to find V₀

V₀ = 2 / [cos(32°) (0.38) ] = 6.2 m/s

8 0
1 year ago
Read 2 more answers
Suppose a1=12−12,a2=23−13,a3=34−14,a4=45−15,a5=56−16. a) Find an explicit formula for an: . b) Determine whether the sequence is
lorasvet [3.4K]

I'm going to assume you meant to write fractions (because if a_n are all non-negative integers, the series would clearly diverge), so that

a_1=\dfrac12-\dfrac12

a_2=\dfrac23-\dfrac13

a_3=\dfrac34-\dfrac14

and so on.

a. If the pattern continues as above, we would have the general term

a_n=\dfrac n{n+1}-\dfrac1{n+1}=\dfrac{n-1}{n+1}

b. Note that we can write a_n as

a_n=\dfrac{n-1}{n+1}=\dfrac{n+1-2}{n+1}=1-\dfrac2{n+1}

The series diverges by comparison to the divergent series

\displaystyle\sum_{n=1}^\infty\frac1n

4 0
2 years ago
En una cancha se va a pintar la circunferencia central que tiene un diámetro de 5 m .¿cual es la longitud de la circunferencia?
Alona [7]

Answer:

The length of the circumference is 5\pi\ m  or 15.70\ m

Step-by-step explanation:

<u><em>The question in English is</em></u>

On a court, the central circumference will be painted, which has a diameter of 5 m. What is the length of the circumference?

we know that

The circumference of a circle is given by the formula

C=\pi D

we have

D=5\ m

substitute

C=\pi (5)\\C=5\pi\ m

This is the exact value

assume

\pi=3.24

C=5(3.14)=15.70\ m

4 0
1 year ago
The heights of 1000 students are approximately normally distributed with a mean of 174.5 centimeters and a standard deviation of
yuradex [85]
A. The mean and standard deviation.

The mean of a sampling distribution is approximately equal to the mean of the population. Given that the mean of the population is equal to 174.5, the mean of the sampling distribution is also this value.

The standard deviation of a sample distribution is equal to,

                u(m) = u/sqrt n

Substituting the known values,

               u(m) = 6.9 / sqrt 25 = 1.38

b. Get the z-score of both items,
         
      z-score = (data point - mean) / standard deviation

 z-score of 172.5
     z-score = (172.5 - 174.5) / 1.38 = -1.49
This translates to 0.068.

z-score of 175.8
   z-score = (175.8 - 174.5) / 1.38 = 0.94
This translates to 0.83. 

The difference between the two z-scores is 0.762. 

 The number of samples with this height is 0.762(200) which is equal to approximately 152.

c. z-score of 172 centimeters
   
    z-score = (172 - 174.5) / 1.38
  
    z-score = -1.81
This translates to 0.03.

The number of people with this height from the sample is (0.03)(200) = 6
8 0
2 years ago
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