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1 year ago

Select the locations on the number line to plot the points −2 , −11 , and −17 .

1 answer:

8 0

Answer: With this information the answer would be GO down twice into the negatives and make you plot point, next go down eleven times and make your plot point, and last go down seventeen times and make your plot point.

Step-by-step explanation: What you have to do is make the number line with a zero at in the middle on the left of the zero you go down into the the negative numbers and on the right you go up into the positive numbers

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Omari drives a car that gets 18 miles per gallon of gasoline. The car's gasoline tank holds 15 gallons. The distance Omari drive

Art [367]

Answer:

Step-by-step explanation:

I believe 9 miles 15x3= 45 gallons what the car holds but he gets 18 mpg

18x3= 54 gallons 54-45=9

3 0

2 years ago

In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . If m∠ADE is with 34° smaller than m∠CAB, find the measures

Charra [1.4K]

Answer:

34°

Step-by-step explanation:

If m∠ADE is with 34° smaller than m∠CAB, then denote

m∠ADE=x°,

m∠CAB=(x+34)°.

Since DE ║ AB, then

m∠ADE=m∠DAB=x°.

AD is angle A bisector, then

m∠EAD=m∠DAB=x°.

Thus,

m∠CAB=m∠CAD+m∠DAB=(x+x)°=2x°.

On the other hand,

m∠CAB=(x+34)°,

then

2x°=(x+34)°,

m∠ADE=x°=34°.

7 0

2 years ago

A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be

Andrei [34K]

Answer:

$\$6,082.70$

Step-by-step explanation:

we know that

The formula to calculate the depreciated value is equal to

$V=P(1-r)^{x}$

where

V is the depreciated value

P is the original value

r is the rate of depreciation in decimal

x is Number of Time Periods

in this problem we have

$P=\$15,300\\r=14.25\%=0.1425\\x=6\ years$

substitute in the formula

$V=15,300(1-0.1425)^{6}$

$V=15,300(0.8575)^{6}$

$V=\$6,082.70$

3 0

2 years ago

Consider the circle of radius 10 centered at the origin. provide answers accurate to two decimal places. (a) the equation of the

Shkiper50 [21]

(a) The equation of the tangent line can be written as
.. 3(x +6) -4(y -8) = 0
.. 3x -4y = -50
.. y = (3/4)x +25/2 . . . the equation of the tangent line

(b) The point of tangency will be the intersection of the circle with the perpendicular line through the circle center, y = (-1/5)x. A graphing calculator shows that point to be
.. (9.81, -1.96)