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Shtirlitz [24]
1 year ago
13

Find the surface area of the regular pyramid shown in the accompanying diagram. If necessary, express your answer in simplest ra

dical form.

Mathematics
1 answer:
Oksana_A [137]1 year ago
4 0

Answer:

The area of the pyramid is 360 unit²

Step-by-step explanation:

Given

Base Edge, a = 10

Height, h = 12

Required

Determine the surface area

The surface area of a regular pyramid is calculated as thus;

A = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}

Substitute values for a and h

A = 10^2 + 2 * 10 * \sqrt{\frac{10^2}{4} + 12^2}

Evaluate all squares

A = 100 + 2 * 10 * \sqrt{\frac{100}{4} + 144}

A = 100 + 2 * 10 * \sqrt{25 + 144}

A = 100 + 2 * 10 * \sqrt{169}

Take positive square root of 169

A = 100 + 2 * 10 * 13

A = 100 + 260

A = 360

<em>Hence, the area of the pyramid is 360 unit²</em>

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A gardener brought 5 rabbits, after 2 months rabbits became 10, and after 4 months they became 20. If the growth continues on th
kramer

Answer:

Initial population of Rabbit = 5 rabbit

After 2 months

Population of Rabbit = 10

After 4 months

population of rabbit = 20

Formula for growth is :

G = G_{0}[1 + R]^n, where G is final population and G_{0} is initial population, and R is growth rate.

1. 10 = 5 [1 +R]²

Dividing both sides by 5 , we get

2 = (1 + R)²

→ R + 1 = √2  ⇒ taking positive root of 2

→R = √2 -1

Amount of rabbit after 1 year = 20(1 + \sqrt2 -1)^8= 20 \times (\sqrt2)^8= 20 \times 2^4= 20 \times 16= 320




6 0
2 years ago
Read 2 more answers
Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
jenyasd209 [6]

Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

3 0
1 year ago
Which point on the number line represents the product (5)(-2)(-1)
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Point +10.

(-2)*(-1) gives +2 (a negative number multiplied for another negative gives a positive number).

2*5 = +10
3 0
1 year ago
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The number of people who attended a concert on Friday was 3/4 the number of people who attended the same concert on Saturday. A
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On Saturday, 4/4 of the amount of people attended.  On Friday, 3/4 of the amount on Saturday attended.  We have 7 parts (3 from Friday and 4 from Saturday).

840/7 = 120.

Thus, 360 people attend on Friday and 480 on Saturday.

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1 year ago
Claire purchases a new dress for the prom. The dress is priced $160, but it is on sale for 30% off. Claire’s aunt works at the s
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The answer should be c. 108.36
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