<span>-|2x-10|-1=2 has NO solutions, because the absolute value function is never negative. Can be 0, can be positive, but can NOT be negative.
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Answer:
11
Fifth term
Step-by-step explanation:
The third term is:
20 − (3)² = 11
If the term is negative:
20 − n² < 0
n² > 20
n > √20
n > 4.47
The first term to have a negative value is the fifth term.
Answer:
168.7602 miles
Step-by-step explanation:
One way to solve this problem is by using an equation that describes the listening radius of the station, and another for the road, then the points where this two-equation intersect each other will represent when the driver starts and stops listening to the station, and the distance between the points is the miles that the driver will receive the signal.
The equation for the listening radius (the radio station is at (0,0)):
The equation for the road that past through the points (-120,0) and (80,100) (Collinsville and Harmony respectively):
Substitutes the value of y in the equation of the circle:
The formula to solve second-degree equations:
Using the values in x to find the values in y:
The distance between the points (51.4718,85.7359) and (-99.4718,10.2641) :
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Answer:
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ASA and AAS
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Step-by-step explanation:
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We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
