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OLga [1]
2 years ago
10

A small coffee shop sells freshly squeezed juices in a refrigerated unit with slots where juice is displayed. These slots are ca

lled facings. The manager of the coffee shop suspects that the distribution of juice sales is different than the distribution of facings for each type of juice, so the manager records the sales of each juice over a two-week period. The proportion of facings and the sales for each type of juice are shown in the tables.
Juice Mango Orange Apple Pineapple Grapefruit Grape
Proportion of Facings 0.1875 0.250 0.250 0.125 0.125 0.0625
Juice Mango Orange Apple Pineapple Grapefruit Grape
Observed Number of Sales 23 35 46 12 10 5
(a) Construct a single bar chart that contains both the expected proportion of sales based on the proportion of facings and the observed proportion of sales for each type of juice.

BoldItalicUnderline

Mathematics
1 answer:
lianna [129]2 years ago
8 0

Answer: kindly check attached picture

Step-by-step explanation:

Given the data below :

Juice Mango Orange Apple Pineapple Grapefruit Grape

Proportion of Facings 0.1875 0.250 0.250 0.125 0.125 0.0625

In other to make the proportion of facing visible on the graph we multiply by 100; Hence,

Juice Mango Orange Apple Pineapple Grapefruit Grape

Proportion of Facings 18.75 2.50 2.50 1.25 1.25 6.25

Juice Mango Orange Apple Pineapple Grapefruit Grape

Observed Number of Sales 23 35 46 12 10 5

(a) Construct a single bar chart that contains both the expected proportion of sales based on the proportion of facings and the observed proportion of sales for each type of juice.

Using an online bar chart plotter, the proportion of facings by the blue bars and the red bars depicts the observalues for different type of juice Given.

Hence, from the plot, it could be clearly seen that the distribution of facing is different or not equal to the number of juice sold.

The barchart produced is attached below.

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Jerome solved the equation below by graphing.
riadik2000 [5.3K]

Jerome rewrote the logarithms as

\log_2x=\dfrac{\log x}{\log2}

\log_2(x-2)]=\dfrac{\log(x-2)}{\log 2}

which eliminates C and D.

Solve the equation:

\log_2x+\log_2(x-2)=\log_2x(x-2)=3\implies 2^{\log_2x(x-2)}=2^3\implies x(x-2)=8

\implies x^2-2x-8=(x-4)(x+2)=0\implies x=4\text{ or }x=-2

\log_b(-2) is undefined for any base b (where the logarithm is real-valued), so we omit that solution.

This makes B the answer.

6 0
2 years ago
Read 2 more answers
A curious student asks his math teacher: "I heard you have three daughters. How old are they?" The math teacher says: "Well, the
scZoUnD [109]

Answer:

There are 7 solutions.

The possible answers are:

The oldest daughter is 72 and the others are 1 and 1 and the room number is 74.

The oldest daughter is 36 and the others are 1 and 2 and the room number is 39.

The oldest daughter is 24 and the others are 1 and 3 and the room number is 28.

The oldest daughter is 18 and the others are 1 and 4 and the room number is 23.

The oldest daughter is 12 and the others are 2 and 3 and the room number is 17.

The oldest daughter is 12 and the others are 1 and 6 and the room number is 19.

The oldest daughter is 9 and the others are 1 and 8 and the room number is 18.

The first few solutions are laughable and unlikely, but all are possible.  

OR..

The clue that the sums of the daughters' ages is the room number is the sleeper.  The student's first response is that two possible age combinations meet the necessary conditions.  The teacher's reference to the "oldest daughter" resolves the ambiguity, so one of the solutions must consist of a set of ages in which at least two of the oldest daughters are the same age.

The prime factors of 72 are 2^3 *3^2.  Because one of the solutions requires the two oldest daughters to be the same age, only combination 6, 6, 2 would be admissible.  There are insufficient factors for any other combination in which the duplicate ages represent the oldest daughter.  The ages of these daughters sum to 14, which is the room number.  The other combination must therefore add to 14 and have an unique oldest age.  The combination 8, 3, 3 meets all conditions and is the answer.

4 0
2 years ago
Question 9 (3 points)
Mila [183]

From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last  names.

---------------------

The dot plot states that:

  • 2 students have 4 vowels in their first and last name.
  • 3 students have 5 vowels.
  • 8 students have 6 vowels.
  • 9 students have 7 vowels.

Then:

  • Total of 2 + 3 + 8 + 9 = 22 students.
  • 3 + 8 + 9 = 20 have or more vowels.

p = \frac{20}{22} \times 100\% = 90.91\%

90.91% of the students have 5 or more vowels in their first and last  names.

A similar problem is given at brainly.com/question/14354536

5 0
2 years ago
What new topics did Isaac Newton discover?
solong [7]
Newton's 3 Laws of Motion are probably the most recognized. 
His universal law Gravitation.
He paved the way for advances in Integral and Differential Calculus. 
5 0
2 years ago
Scott wants to buy fencing to place around a circular rock garden. The diameter of the circle is 16 feet. Using 3.14 for π, Calc
denpristay [2]

Answer:

200.96 square feet

Step-by-step explanation:

The amount of fencing Scott will need to buy can be gotten by calculating the area of the circular rock garden .

Area of a circle is given by

Pi r^2

Where

r = radius

Given diameter of 16 feet

r = diameter/2

= 16/2

= 8 feet

Pi = 3.14

Therefore,

Area = 3.14 x 8^2

= 3.14 x 8 x 8

= 200.96 square feet

The amount of fencing Scott will need to buy is 200.96square feet

5 0
2 years ago
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