Can you Solve this?<br> IF AT=4 CAT=6 CROW=8 BRAIN=10<br><br> TWISTER = ?

1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas d

TiliK225 [7]

Answer:

1. The amount that was not spent is: 1080 soles

2. The answer is 5.

Step-by-step explanation:

Question 1. There are two situations:

If you spent 5/8 of the money then notice, that u did not spend 3/8.

If you spend 2/5 of the money, then you would have 72 more.

So think, this equation:

3/8x + 72 = 2/5x

2/5 of the money is the value for what you did not spend plus 72, the amount you would have, where x is the answer for the total of money.

72 = 2/5x - 3/8x

72 = 1/40x

x = 2880 soles

As you did not spend 3/8 of 2880, the answer is 1080 soles

Notice that if u spent 2/5 of 2880, you would have 1152 soles, so, the 1080 + 72, as the problem said.

Question 2.

We think letters for this excersise.

N = My born year

2020 (this year) - N = E (my age, now)

So N + 10 = when I get 10 years old

N + 20 = when I get 20 years old

N + 30 = when I get 30 years old

N + 40 = when I get 40 years old

The problem says:

(N+10) + (N+20) - (N+E) = 2020

((N+30)+E) - (N-40) = X

So if 2020 - N = E, then notice that 2020 - E = N. Let's replace this in the equation form:

((2020-E)+10) + ((2020-E)+20) - ((2020-E)+E) = 2020

No minus in the first two terms, so we can break the ( )

2020-E+10 + 2020-E+20 - ((2020-E)+E) = 2020

We apply the distributive property for the second term

2020-E+10 + 2020-E+20 - 2020+E-E = 2020

We can cancel two E, and the 2020, so the new form will be:

2020 - 2E + 30 = 2020

We can also cancel the 2020, so if we reorder the equation, we have:

-2E = -30

E = 15 That's my age, so my born's year is 2020 - 15 = 2005 (N)

Look:

(2005 + 10) + (2005+20) - (2005+15) = 2020

So now, the last part

((2005+30)+15) - (2005+40) = 5

3 0

1 year ago

What number would you multiply the second equation by in order to eliminate the x-terms when adding to the first equation? What

alexandr402 [8]

Answer:

1. Multiply (2) by 2 to eliminate the x-terms when adding

2. Multiply (2) by 3 to eliminate the y- term

Step-by-step explanation:

Use this system of equations to answer the questions that follow.

4x-9y = 7

-2x+ 3y= 4

what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 2 to eliminate the x-terms when adding the first equation

4x-9y = 7

-4x +6y = 8

Adding the equations

4x + (-4x) -9y + 6y = 7 + 8

4x - 4x - 3y = 15

-3y = 15

y = 15/-3

= -5

what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 3 to eliminate the y- term

4x - 9y = 7

-6x + 9y = 12

Adding the equations

4x + (-6x) -9y + 9y = 7 + 12

4x - 6x = 19

-2x = 19

x = 19/-2

= -9.5

x = -9.5

6 0

1 year ago

Read 2 more answers

The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are

n200080 [17]

Answer:

$Z_{H_0}= -1.85$

Step-by-step explanation:

Hello!

The high school dropout rate, as a percentage of 16- through 24- year-olds who are not enrolled in school and have not earned a high school credential was is 2009 8.1%.

To thest the claim that this percentage has decreased, a polling company takes a random sample of 1000 people between the ages of 16 and 24 and finds out that 6.5% of them are highschool dropouts.

The study variable is

X: Number of individuals with age between 16 and 24 years old that are highschool dropouts.

The parameter of interest is the proportion fo highschool dropouts p

And the sample proportion is p'= 0.065

The hypotheses are:

H₀: p ≥ 0.081

H₁: p < 0.081

To study the population proportion, you have to approximate the distribution of the sampling proportion to normal applying the Central Limit Theorem, then the statistic to use is an approximate standard normal:

$Z_{H_0}= \frac{(p'-p)}{\sqrt{\frac{p*(1-p)}{n} } } = \frac{0.065-0.081}{\sqrt{\frac{0.081*0.919}{1000} } } = -1.85$

I hope this helps!

3 0

2 years ago

Which description best compares the graphs of the two functions below?

Pavlova-9 [17]

Some of your pic is cut off so it's difficult to give the exact answer. But if you plot the points from the table you get that the equation for that set of data is linear and is y = 1/3x -2. This tells me that the y-intercepts are the same for both equations, so your answer is not the first or the third. Because the slope of the function A is 3 and for B is 1/3, the line for function A is steeper, the second of your choices above.

7 0

2 years ago

Read 2 more answers

A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T

Lady_Fox [76]

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of 10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

8 0

2 years ago

Can you Solve this? IF AT=4 CAT=6 CROW=8 BRAIN=10 TWISTER = ?