Question

A frame around a rectangular family portrait has a perimeter of 60 inches. The length is 15 inches less than 2 times the width. Find the length and width of the frame

Answer 1

2(2w-5) + 2w = 50

4w - 10 + 2w = 50

6w - 10 = 50

6w = 60

w = 10

length is 2(10) - 5 = 20 -5 = 15

i hope this helps!!

Answer 2

Answer:

Step-by-step explanation:

Let x be the width of the  rectangular family portrait  , then its length will be 2x-15.

Formula to find perimeter :-

$P=2(l+w)=2(2x-15+x)\\\\\Rightarrow\ P=2(3x-15)=6x-30$    (1)

Since, the perimeter of the frame = 60 inches, then substitute P=60 in (1), we get

$60=6x-30$

Add 30 both sides , we get

$6x=90$

Divide 6 on both sides , we get

$x=15$

hence, Width = 15 inches

Length = 2(15)-15=15 inches.

Hence, the  length and width of the frame are 15 inches by 15 inches.