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marshall27 [118]
2 years ago
8

Shota invests $1000 in a certificate of deposit that earns interest. The investment’s value is multiplied by 1.02 each year. Whi

ch expression gives the investment’s value after 5 years?
Mathematics
2 answers:
jek_recluse [69]2 years ago
7 0

Answer:

1000⋅1.02^5

Step-by-step explanation:

I just did it

DENIUS [597]2 years ago
5 0

Answer:

1020

Step-by-step explanation:

1000 times 1.02

here the answer will be 1020.

step-by-step explanation:

1000 times 1.02= 1020

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A student has an allowance of $20 a week. He wants to buy lunch at school for $3.50 everyday. Does this student have enough mone
Alex787 [66]

Answer:

no

Step-by-step explanation:

in a 7 day week, he would need $24.50

8 0
2 years ago
A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
maxonik [38]

Answer:

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

p_v =2*P(z>1.413)=0.158  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:  

Null hypothesis:\mu = 5  

Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>1.413)=0.158  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

8 0
2 years ago
Triangle FGH with vertices F(1,8), G(5,7), and H(2,3) in the line y=x.
sergiy2304 [10]
Check Hathaway they will
4 0
2 years ago
Read 2 more answers
The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
Slav-nsk [51]

\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

The prices of three t-shirts styles  i.e $24, $30, $36 with their probability is given by

\frac{1}{6}, \frac{1}{2},\frac{1}{3}

As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

\text{where} x_i \text{ is the prices of t- shirts styles}

Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}

So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

So, the expected value of a t-shirt = $31.

4 0
2 years ago
Consider the system of inequalities and its graph. y ≤ –0.75x y ≤ 3x – 2 On a coordinate plane, 2 solid straight lines are shown
ella [17]

Answer:

4

Step-by-step explanation:

the answer is 4 so d on edge .

8 0
2 years ago
Read 2 more answers
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