Answer:
Inherently asymmetrical casual relationship.
Step-by-step explanation:
The dog owners are given free dog food samples which contain new vegetables. These samples are given to them by organizing booths at the dog events. The reaction of the dog owners is observed towards this new dog food. This an example of inherently asymmetrical relationship.
Answer:
6x + 4y ≤ 50
x + y ≥ 10
Step-by-step explanation:
$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.
The equation would be y=2.10x+3.25!
Also know as A lol
If you plug in 9 as x and add 3.25 it is an easy way to check the answers for further questions!
Have a good day! :-)
If it is not correct or doesn't look quite right or needs to show proof please comment!
Answer: ![3ab\sqrt[3]{b^4}](https://tex.z-dn.net/?f=3ab%5Csqrt%5B3%5D%7Bb%5E4%7D)
Step-by-step explanation:
Given the following expression:
![\sqrt[3]{27a^3b^7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E3b%5E7%7D)
You need to apply the Product of powers property, which states that:
Then, you can rewrite the expression as following:
![=\sqrt[3]{27a^3b^4b^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B27a%5E3b%5E4b%5E3%7D)
The next step is to descompose 27 into its prime factors:
Now you must substitute 
inside the given root. Then:
![=\sqrt[3]{3^3a^3b^4b^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%5E3a%5E3b%5E4b%5E3%7D)
You need to remember that, according to Radicals properties:
![\sqrt[n]{a^n}=a^{\frac{n}{n}}=a^1=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5E%7B%5Cfrac%7Bn%7D%7Bn%7D%7D%3Da%5E1%3Da)
Therefore, the final step is to apply this property in order to finally get the expression is its simplest form. This is:
![=3^{\frac{3}{3}}a^{\frac{3}{3}}b^{\frac{4}{3}}b^{\frac{3}{3}}=3ab^{\frac{4}{3}}b=3ab\sqrt[3]{b^4}](https://tex.z-dn.net/?f=%3D3%5E%7B%5Cfrac%7B3%7D%7B3%7D%7Da%5E%7B%5Cfrac%7B3%7D%7B3%7D%7Db%5E%7B%5Cfrac%7B4%7D%7B3%7D%7Db%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3D3ab%5E%7B%5Cfrac%7B4%7D%7B3%7D%7Db%3D3ab%5Csqrt%5B3%5D%7Bb%5E4%7D)
2 possibilities for each person, for 8 people
= 2*2*2*2*2*2*2*2
=2^8
= 256 ways of announcing the result
