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Elden [556K]
2 years ago
7

A preimage includes a line segment with a length of x units and a slope of m units. The preimage is dilated by a scale factor of

n. The length of the corresponding line segment in the image is (x, or nx) units. The slope of the corresponding line segment in the image is (m, or nm) .
Mathematics
2 answers:
lapo4ka [179]2 years ago
8 0
Nx is the first one  and m is the second answer
Anastasy [175]2 years ago
7 0

Answer:

Slope becomes m

length becomes nx

Step-by-step explanation:

Slope:

We know that

slope is the ratio of change in y-value and change in x-value

so, dilation do not change slope of any line

so, after dilation

m---->m

Length of line:

we know that

A dilation has the effect of stretching or shrinking the line segment by the factor of m units

we are given

length of line =x

so, it's length will become

=n\times x

=nx

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A newly introduced fitness program is gaining popularity among the members of a fitness club. The number of members, s(1), who j
ahrayia [7]

Answer:

Option A will be the answer.

Step-by-step explanation:

The number of members, s(t), who joined the  program t months after it was introduced is modeled by the function below  

s(t) = 10(2)^{x}  + 10

The function is an exponential function and y-intercept of the function is at (0,20) point.

Now, from the graph given in the options, the first graph matches the criteria.

Hence, option A will be the answer. (Answer)

6 0
2 years ago
96.5 times 2.54 i know the answer i just need help showing the work
kogti [31]
You just solve it like a normal multiplication problem and then start putting the decimal begin the answer and place it 3 numbers forward
3 0
2 years ago
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A team of 10 players is to be selected from a class of 6 girls and 7 boys. Match each scenario to its probability. You have to d
tankabanditka [31]
The selection of r objects out of n is done in

C(n, r)= \frac{n!}{r!(n-r)!} many ways.

The total number of selections 10 that we can make from 6+7=13 students is 

C(13,10)= \frac{13!}{3!(10)!}= \frac{13*12*11*10!}{3*2*1*10!}= \frac{13*12*11}{3*2}=  286
thus, the sample space of the experiment is 286

A. 
<span>"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.


</span>C(7, 4)= \frac{7!}{4!3!}= \frac{7*6*5*4!}{4!*3*2*1}= \frac{7*6*5}{3*2}=35
<span>
P(all 6 girls chosen)=35/286=0.12

B.
"</span>The probability that a randomly chosen team has 3 girls and 7 boys.<span>"

with the same logic as in A, the number of groups were all 7 boys are in, is 

</span>C(6, 3)= \frac{6!}{3!3!}= \frac{6*5*4*3!}{3!3!}= \frac{6*5*4}{3*2*1}=20
<span>
so the probability is 20/286=0.07

C.
"</span>The probability that a randomly chosen team has either 4 or 6 boys.<span>"

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is </span>0.12.
<span>
case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls. 

</span>C(7, 6)*C(6, 4)= \frac{7!}{6!1}* \frac{6!}{4!2!} =7*15= 105
<span>
the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.
"</span><span>The probability that a randomly chosen team has 5 girls and 5 boys.</span><span>"

selecting 5 boys and 5 girls can be done in 

</span>C(7, 5)*C(6,5)= \frac{7!}{5!2} * \frac{6!}{5!1}=21*6=126

many ways,

so the probability is 126/286=0.44
6 0
2 years ago
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What is 4973 divided by 7
Firlakuza [10]
The answer is 710.42
3 0
2 years ago
Read 2 more answers
Form a sequence that has two arithmetic means between -1 and 59.
Oksanka [162]
The formula for solving the problem is as follow:
an = a1 + (n - 1)d
Where:
n = number of figure in the sequence = 4
d = difference between successive number =?
a1 = -1
a4 = 59
Insert the given values into the formula,
59 = -1 + (4 - 1)d
59 = -1 + 3d
59 + 1 = 3d
60 = 3d
d = 60/3 = 20
Therefore, d = 20. This implies that, there is a difference of 20 between successive numbers.
The number sequence is as follow:
-1, 19, 39, 59.

7 0
1 year ago
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