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devlian [24]
2 years ago
13

21. Given directed line segment WV , find the coordinates of R

Mathematics
1 answer:
Jobisdone [24]2 years ago
6 0

Answer:

R\left(\frac {4x_1+3x_2}{7} , \frac {4y_1+3y_2}{7}\right)

Step-by-step explanation:

Let the coordinate of the points W, V and R are (x_1,y_1), (x_2,y_2), and (x_s,y_s)respectively.

The coordinate of the section point, (x_s,y_s), which divides the line joining the two points (x_1,y_1) and (x_2,y_2) in the ration m:n is

x_s=\frac {nx_1+mx_2}{m+n} and

y_s=\frac {ny_1+my_2}{m+n}.

The given ration is, m:n=3:4

R(x_s,y_s)=R\left(\frac {nx_1+mx_2}{m+n} , \frac {ny_1+my_2}{m+n}\right)

=R\left(\frac {4x_1+3x_2}{7} , \frac {4y_1+3y_2}{7}\right).

The exact point can be determined by putting the value of the exact coordinate in the above-obtained formula.

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The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave
kkurt [141]

Answer:

<u>0.9524</u>

Step-by-step explanation:

<em>Note enough information is given in this problem. I will do a similar problem like this. The problem is:</em>

<em>The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?</em>

<em />

<u>Solution:</u>

This is conditional probability.

Given:

  • Probability train arrive on time and leave on time = 0.8
  • Probability train arrive on time = 0.84
  • Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

P(Leave \ on \  time | arrive \  on \ time) = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = <u>0.9524</u>

<u></u>

<u>This is the answer.</u>

5 0
2 years ago
A land surveyor places two stakes 500 ft apart and creates a perpendicular to the line that connects these two stakes. He needs
cupoosta [38]

Answer:
We will choose the last option is correct.
Step-by-step explanation:
A land surveyor places two stakes 500 ft apart and locates the midpoint between the stakes.
From the midpoint, he needs to place another stake 100 ft away that is equidistant to the two original stakes.  
Therefore, to apply the Perpendicular Bisector Theorem, the land surveyor would have to identify a line that is "perpendicular to the line connecting the two stakes and going through the midpoint of the two stakes".
Therefore we will choose the last option is correct. (Answer)

8 0
2 years ago
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A sailor judges the distance to a lighthouse by holding a ruler at arm's length and measuring the apparent height of the lightho
Oksanka [162]

Solution:

Actual Height of Light House = 60 Feet

Comparing with the ruler

Height of Ruler = 3 inches

Distance between eye and Ruler = 2 feet

Let Actual Distance between Light house and Ruler = x feet

As the two triangles are similar by AA Criteria, so their sides  will be proportional to each other, i.e

\frac{60}{3}=\frac{x}{2}\\\\ 20=\frac{x}{2}\\\\ x=40 feet

So, Distance between Light house and Ruler = 40 feet


6 0
2 years ago
Read 2 more answers
The amount of mustard dispensed from a standard dispenser is normally distributed with a mean of 0.9oz and a variance of 0.01oz.
lubasha [3.4K]

Answer:

the probability that more than 3 of them will have more than one ounce of mustard is 0.05975

Step-by-step explanation:

Given te data in the question;

let x rep the quantity of mustard on a hotdog ( in oz)

so

X → N ( u = 0.9, α² = 0.01 )

now P( more than one ounces of mustard on a hotdog) will be

P( X>1 ) = P( Z > ((1-0.9)/(√0.01)) ) = P( Z > 1 ) = 1 - P( Z < 1 )

= 1 - 0.84134 = 0.15866

Also let Y rep the number of hotdogs that have more than one ounces of mustard, so

Y → Bin( n = 10, p = 0.15866 )

P( y = y ) = (¹⁰ _y) ( 0.15855)⁰ ( 1 - 0.15866 )^10-y, y = 0,1,2,3......, 10

so required probability = P(Y > 3) = 1 - P(Y ≤ 3)

= 1 - P(Y=0) - P(Y=1) - P(Y=2) - P(Y=3)

=1 -  (¹⁰ ₀) ( 0.15855)⁰ (1 - 0.15855)¹⁰⁻⁰ - (¹⁰ ₁) ( 0.15855)¹ (1 - 0.15855)¹⁰⁻¹ - (¹⁰ ₂) ( 0.15855)² (1 - 0.15855)¹⁰⁻² - (¹⁰ ₃) ( 0.15855)³ (1 - 0.15855)¹⁰⁻³

= 0.05975

Therefore the probability that more than 3 of them will have more than one ounce of mustard is 0.05975

4 0
2 years ago
The table shows the shipping costs for items of different values. A 2-column table with 4 rows. The first column is labeled tota
Lisa [10]

A strong positive correlation.

Step-by-step explanation:

The question requires you to calculate the correlation coefficient and then make a conclusion about its value.

Form a table as shown where x is cost of items and y is shipping cost

x               y           xy                   x²         y²

25           5.99       149.8          625         35.9

45            8.99       404.6       2025        80.8

50            8.99      449.5         2500       80.8

70            10.99      769.3         4900       120.8

190           34.96     1773.2        10050      318.3 ------sum

The formula for correlation coefficient follows;

r=n(∑xy)-(∑x)(∑y) ÷ √{[n∑x²-(x)²] [n∑y²-(y)²]}

where n=4

r=4(1773.2)-(190)(34.96) ÷ √{[4(10050)-190²] [4(318.3)-34.96²]}

r=450÷ √{4100*51)

r=450÷√209100

r=450÷457.3

r=0.98409

The value of r indicates a stronger positive correlation

Learn More

Correlation coefficient :brainly.com/question/12528676

Keywords :shipping costs,cost of items, strength of the model

#LearnwithBrainly

4 0
2 years ago
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