Answer:
We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.
Step-by-step explanation:
Let's first list the percentage compositions of each fertilizer type:
<u>Vigoro Ultra Turf:</u>
Nitrogen (N) = 29 kg
Phosphoric Acid (P2O5) = 3 kg
Potash (K2O) = 4 kg
<u>Parkers Premium</u>
Nitrogen (N) = 18 kg
Phosphoric Acid (P2O5) = 25 kg
Potash (K2O) = 6 kg
We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:
x = Vigoro Ultra turf (one bag)
y = Parkers Premium (one bag)
29x + 18y = 217 -Equation 1
3x + 25y = 115 -Equation 2
4x + 6y = 44 -Equation 3
Solving for x and y, we get:
x = 5
y = 4
This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.
Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :

Distance of P from ( -3, 4 ) :

Now , these distance are equal :

Solving above equation , we get :

Hence , this is the required solution.
The answer would be ΔKML because the right angle of ΔKML is in the same place as <span>ΔJKL</span>
M∠X = 54.3°.
Using the Law of Sines, we have:

Cross multiplying gives us
61(sin 34) = 42(sin X)
Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X
Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
54.3 = X