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Alenkasestr [34]
2 years ago
12

Your model locomotive is 16 inches long. It is an exact model of a locomotive that is 40 feet long. A window on the locomotive i

s how many times wider than a window on the model?
Mathematics
1 answer:
Ierofanga [76]2 years ago
7 0
1 feet is 12 inches so 40 feets is 480 inches
Real locomotive is 480/16=30 times wider then the model
And then a window on the real locomotive is 30 times wider then the model.
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Jan accidentally ran 7 minutes longer than she was supposed to. Write an expression for the total amount of time Jan ran if she
vovangra [49]

Answer:

m+7

Step-by-step explanation:

If she ran 7 minutes longer and m represents the amount of time she ran, then it would just be addition.

Let's say m=60 minutes. She would've ran for 67 minutes, which is also m+7.

6 0
2 years ago
a(0.3−y)+1.1+2.4x (y−1.2) ​ =0 =−1.2(x−0.5) ​ Consider the system of equations above, where aaa is a constant. For which value o
Veseljchak [2.6K]

Answer:

For a = 1.22 there is one solution where y = 1.3

Step-by-step explanation:

Hi there!

Let´s write the system of equations:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

-1.2(x-0.5) = 0

Let´s solve the second equation for x:

-1.2(x-0.5) = 0

x- 0.5 = 0

x = 0.5

Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0

a(-1) + 1.1 + 1.2(0.1) = 0

-a + 1.22 = 0

-a = -1.22

a = 1.22

Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:

1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0

0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0

-0.02y +0.026 = 0

-0.02y = -0.026

y = -0.026 / -0.02

y = 1.3

Then, the answer is correct.

Have a nice day!

4 0
2 years ago
The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
2 years ago
A scientist is studying red maple tree growth in a state park. She measured the trunk diameters of a sample of trees in the same
Genrish500 [490]
The answer will beee (A.22)
3 0
2 years ago
Read 2 more answers
Without properly working spark plugs, a vehicle will not run. For a specific vehicle, the spark plugs are supposed to have a gap
Salsk061 [2.6K]

Answer:

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the mean of the Normal distribution = 4.1mm</em>

<em>Given that the standard deviation of the Normal distribution = 0.0075mm</em>

<em>Let 'X' be the random variable in a normal distribution</em>

Given that X₁ = 3.9mm

Z_{1} = \frac{X_{1} -mean}{S.D}

Z_{1} = \frac{3.9 -4.1}{0.075} =  -2.666

Given that X₂ = 4.3mm

Z_{2} = \frac{X_{2} -mean}{S.D}

Z_{1} = \frac{4.3 -4.1}{0.075} =  2.666

<u><em>Step(ii):-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3) = P(-2.666≤Z≤2.666)</em>

<em>                      = P(Z≤2.666)-P(Z≤-2.666)</em>

<em>                     = 0.5 +A(2.666) - (0.5-A(2.666)</em>

<em>                    = 2 × A(2.666)</em>

<em>                  = 2×0.4961</em>

<em>                  = 0.9922</em>

<u><em>Final answer:-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

<em></em>

3 0
1 year ago
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