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denpristay [2]
2 years ago
5

Cameron has a mask collection. He keeps 267 of the masks on his wall, which is 89%

Mathematics
2 answers:
Marat540 [252]2 years ago
6 0

Answer:

300 masks

Step-by-step explanation:

89% = 0.89

( / ) = divided by

267/total amount of masks = 0.89

267/0.89 = 300

300 masks in total

Firdavs [7]2 years ago
3 0

Answer:

300 masks

Step-by-step explanation:

If 267 is 89% of the whole amount, we can set up the following proportion:

\frac{89}{100} =\frac{267}{x}, where x is the total amount of masks we need to find.

If we cross-multiply, we get 26700=89x. Divide both sides by 89, and we get 300. So, Cameron has a total of 300 masks in his collection.

I hope this helped.

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The temperature in Montreal was -8° C. In New York the temperature was 11° C. How many degrees warmer was the temperature in New
jeka57 [31]

Answer:

19

Step-by-step explanation:

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2 years ago
A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

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After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

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4 0
2 years ago
Find the value of sin100.sin120.sin140.sin160​
NARA [144]

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Step-by-step explanation:

To find the value of sin100.sin120.sin140.sin160, let us find the value of each angle.

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Substituting the values of sin, we get,

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Multiplying the values of sin, we get,

sin100.sin120.sin140.sin160=0.1875

Thus, the value of sin100.sin120.sin140.sin160 is 0.1875

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diamong [38]

Answer:

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3 0
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Which of the following explains how ΔAEI could be proven similar to ΔDEH using the AA similarity postulate?
umka2103 [35]

Answer:

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Step-by-step explanation:

tbh im not suuper sure but my educated guess is that by looking at it. Good Luck!

4 0
2 years ago
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