Question

What is the sum? StartFraction 3 y Over y squared + 7 y + 10 EndFraction + StartFraction 2 Over y + 2 EndFraction

Answer 1

Answer:

$\dfrac{5}{y+5}$

Step-by-step explanation:

Here, we have to find the sum of 2 fractions:

1st fraction: $\dfrac{3y}{y^{2}+7y+10}$

2nd fraction: $\dfrac{2}{y+2}$

Considering the denominator of 1st fraction:

$y^{2}+7y+10$

Using factorization method:

$7y$ can be written as $(2y + 5y)$.

$\Rightarrow y^{2}+2y+5y+10$

Taking 5 common from $5y+10$ and y common from $y^{2}+2y$: $\Rightarrow y(y+2)+5(y+2)$

Now taking $(y+2)$ common:

$\Rightarrow (y+5)(y+2)$

$\dfrac{3y}{y^{2}+7y+10}$ can be written as $\dfrac{3y}{(y+5)(y+2)}$

Now, calculating the sum:

$\dfrac{2y}{(y+5)(y+2)} + \dfrac{2}{y+2}$

Taking LCM and solving:

$\Rightarrow \dfrac{3y+2(y+5)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5y+10}{(y+5)(y+2)}\\\Rightarrow \dfrac{5(y+2)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5}{(y+5)}$

Hence, answer is $\dfrac{5}{y+5}$.