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Vedmedyk [2.9K]
2 years ago
14

A 6-kg bag of fertilizer covers a rectangular area of 2.5 m by 5.0 m.

Mathematics
1 answer:
Naily [24]2 years ago
8 0

Answer

Given,

Mass of bag = 6 Kg

Area covered by the bag = 2.5 x 5 = 12.5 m²

a) Bags required to cover area = 7.5 x 10.2

                                                    = 76.5 m²

 Number of bags, N = \dfrac{76.5}{12.5}

                               N = 6.12 = 7 (approx.)

7 Bags of 6 Kg fertilizers will be needed to cover the area.

b) Cost of 6 Kg fertilizers = $15.50

  Cost of 7 bags of 6 Kg fertilizers = 7 x $15.50

                                                         = $108.50.

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P(\dfrac{X-545}{100}< \dfrac{n-545}{100})=0.95
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2 years ago
The larger nail is a dilation of the smaller nail.
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Answer:

The Answer Is (C.)

Step-by-step explanation:

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Cameron bought twelve pounds of candy corn for 79 cents a pound and eighteen pounds of M&amp;Ms for $1.09 a pound, planning to m
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2 years ago
A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

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5 0
2 years ago
In a regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample points in the sample space
posledela

Answer: a.) 40320

b.) 336

Step-by-step explanation:

since we have 8 possible positions, with 8 different candidates, then there are 8 possible ways of arranging the first position, 7 possible ways of arranging the Second position, 6 ways of arranging the 3rd position, 5 possible ways od arranging the 4th position, 4 possible ways of arranging the 5th position, 3 possible ways of arranging the 6th position, 2 possible ways of arranging the 7th position and just one way of arranging the 8th position since we have only one person left.

Hence, the Number of possible sample space for different 8 positions is by multiplying all the number of ways we have in our sample space which becomes:

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b.) By the sample space we have, since we've been asked ti arrange for only the firat 3 positions, then we multiply just for the first 3ways of choosing the positions, this becomes:

8*7*6 = 336

5 0
2 years ago
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