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Pepsi [2]
2 years ago
11

A large department store is curious about what sections of the store make the most sales. The manager has data from ten years pr

ior that show 30% of sales come from Clothing, 25% Home Appliances, 18% Housewares, 13% Cosmetics, 12% Jewelry, and 2% Other. In a random sample of 550 current sales, 188 came from Clothing, 153 Home Appliances, 83 Housewares, 54 Cosmetics, 61 Jewelry, and 11 Other. At α=0.10, can the manager conclude that the distribution of sales among the departments has changed? Enter the p-value - round to 4 decimal places. Make sure you put a 0 in front of the decimal.
Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

Answer:

Hypotheses:

H0: There is no difference in the distribution of current sales.

H1: There is a difference in the distribution of current sales.

Enter the test statistic - round to 4 decimal places. 23.0951

Enter the p-value - round to 4 decimal places. 0.0003

Can it be concluded that there is a statistically significant difference in the distribution of sales?

Yes

please mark me brainliest!

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kenny6666 [7]

Answer & Step-by-step explanation:

8s - (5s + 6)= 12(20+6s)

8s - 5s - 6 = 240 + 72s

3s - 6 = 240 + 72s

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s= -246/69

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Hope this helps!!!

7 0
2 years ago
Which exponential expression is equivalent to the one below?
OverLord2011 [107]

Answer:

The answer is A.

Step-by-step explanation:

You have to elaborate it :

{(54 \times ( - 13))}^{66}

=  {(54)}^{66}  \times  {( - 13)}^{66}

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2 years ago
Evaluate y = ln (x − 2) for the following values of x. Round to the nearest thousandth.
MatroZZZ [7]

Answer:

0

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Step-by-step explanation:

5 1
2 years ago
Read 2 more answers
The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
Rina8888 [55]

Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

5 0
2 years ago
Calculate δe, if q= 0.764 kj and w= -830 j . express your answer using two significant figures.
Deffense [45]
Given:
Q = 0.0764 kJ = 764 J, heat input
W = -830 J, useful work done

From the 1st Law of Thermodynamics, the change in internal energy is
δE = Q - W
     = 764  - (-830)
     =  1594 J = 1.594 kJ

Answer: 1.59 kJ (two sig. fig.)
8 0
2 years ago
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