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Hoochie [10]
2 years ago
14

Which of the following is true for f(x) = 5cos(x) +1?

Mathematics
2 answers:
e-lub [12.9K]2 years ago
7 0

Answer:

D

Step-by-step explanation:


prisoha [69]2 years ago
5 0

The function f(x)=5cos(x)+1 is the cosine curve with 5 as the amplitude and is shifted 1 units up.

Let's check all the 4 choices:

A.

The period of a function in the form f(x)=Acos(x)+B (which is the function in this problem) has period 2\pi. Period would have changed if there was any coefficient of x in the argument. But it doesn't so period is NOT 10\pi.

B.

The amplitude of a function in the form f(x)=Acos(x)+B (which is the function in this problem) is A. But A is 5 here so the amplitude is definitely NOT 2.5.

C.

A zero of the function is given as (\frac{\pi}{2},0), which means that if we plug in \frac{\pi}{2} into x, it should give us 0. Let's check:

5cos(\frac{\pi}{2})+1\\=5(0)+1\\=1. It's not true.

D.

We know that this function has an amplitude of 5, so the part 5cos(x) ranges from -5 to 5. But this part is shifted 1 units up, so the max amplitude is 5+1=6 and the min is -5+1=-4. So we can say that the range of the function is the set of real numbers from -4 to 6. This choice is correct.

ANSWER: Last choice, choice D.

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First, let's subtract the whole pool by the water currently in to find the water needed to fill it:
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In parallelogram ABCD , diagonals AC⎯⎯⎯⎯⎯ and BD⎯⎯⎯⎯⎯ intersect at point E, AE=x2−16 , and CE=6x .
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Answer:

<h3>AC=96 units.</h3>

Step-by-step explanation:

We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.

AE=x^2-16. , and CE=6x .

<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>

Therefore, AE = EC.

Plugging expressions for AE and EC, we get

x^2-16=6x.

Subtracting 6x from both sides, we get

x^2-16-6x=6x-6x

x^2-6x-16=0

Factoriong quadratic by product sum rule.

We need to find the factors of -16 that add upto -6.

-16 has factors -8 and +2 that add upto -6.

Therefore, factor of x^2-6x-16=0 quadratic is (x-8)(x+2)=0

Setting each factor equal to 0 and solve for x.

x-8=0  => x=8

x+2=0  => x=-2.

We can't take x=-2 as it's a negative number.

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According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 –
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We have to identify the function which has the same set of potential rational roots as the function g(x)= 3x^5-2x^4+9x^3-x^2+12.

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Let 'p' be the factors of 12

So, p= \pm 1, \pm 2, \pm 3, \pm 4, \pm 6

Let 'q' be the factors of 3

So, q=\pm 1, \pm 3

So, the rational roots are given by \frac{p}{q} which are as:

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Here also, Let 'p' be the factors of 12

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