We cannot use CPCTC to show that BE is congruent to DE.
CPCTC refers to the angles and sides of two congruent triangles being congruent to their corresponding pieces. The height of a triangle is not one of the given sides that counts in this.
Answer:
The circumference of the sphere is
or 
Step-by-step explanation:
step 1
Find the radius of the sphere
we know that the volume of the sphere is equal to

we have

substitute and solve for r

assume



step 2
Find the circumference
The circumference is equal to

we have

substitute


assume


Answer:
<em>c=6, d=2</em>
Step-by-step explanation:
<em>Equations
</em>
We must find the values of c and d that make the below equation be true
![\sqrt[3]{162x^cy^5}=3x^2y \sqrt[3]{6y^d}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%3D3x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D)
Let's cube both sides of the equation:
![\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3](https://tex.z-dn.net/?f=%5Cleft%20%28%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%5Cright%20%29%5E3%3D%5Cleft%20%283x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D%5Cright%29%5E3)
The left side just simplifies the cubic root with the cube:
![162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3](https://tex.z-dn.net/?f=162x%5Ecy%5E5%3D%5Cleft%20%283x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D%5Cright%29%5E3)
On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

Simplifying

Equating the powers of x and y separately we find
c=6
5=3+d
d=2
The values are

Mil seiscientos ochenta,centímetros; le quedan a La tienda Malik’s. 3200-1520=1680 cm