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2 years ago

The value of the x- intercept for the graph of 4x-5y=40 is

Mathematics

1 answer:

andrew-mc [135]2 years ago

8 0

4x - 5y = 40

4x = 40 + 5y
x = 10 + 5/4y

The x intercept is 10.

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A scatterplot consists of (1, 4.0), (2, 3.3), (3, 3.8), (4, 2.6), and (5, 2.7). The line of best fit used to model the data is y

zhenek [66]

Answer:

Step-by-step explanation:

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2 years ago

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Find the hcf of 144 and 180. if it is expressed in the form 13m-3, find the value of m

BaLLatris [955]

Answer:

Step-by-step explanation:

To find the HCF of 144 and 180

By using product of prime method

Firstly express 144 as a product of it prime and express 180 as a product of it prime

140=2×2×2×2×3×3

180=2×2×3×3×5

Common factor =2×2×3×3

in term of m

m=36

13m-3

To find m

Substitute for m when m=36

13(36)-3=

465

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2 years ago

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Use forward and backward difference approximations of O(h) and a centered difference approximation of O(h2) to estimate the firs

strojnjashka [21]

Answer:

Answer has explained below.

Step-by-step explanation:

Consider the function is:

F(x) = 25x3 – 6x2 +7x -88

Differentiate with respect to x, we get

F’(x) = 25. 3x2 – 6.2x + 7

= 75x2 – 12x +7

At x = 2, we have

F (2) = 25(2)3 – 6(2)2 + 7(2)-88

=102

And f’(2) = 75(2)2 – 12 (2) +7

=283

Now, calculate forward divided difference as:

xi + 1 = xi + h

=2 + 0.25

=2.25

F (xi + 1) = f (2.25) = 25 (2.25)3 – 6(2.25)2 +7(2.25) -88

=182.21

f’(2) = f(2.25) – f(2) / 0.25 = 182.21 – 102 / 0.25

= 320.84

Єt = 283 – 320.8 / 283 = -13.36%

Now calculate backward divided difference:

Xi-1 = xi –h = 2 – 0.25 = 1.75

F(xi-1)= f(1.8) = 25 . (1.8)3 -6 (1.8)2 + 7 (1.8) – 88

= 50.96

F’(2) = f(2) – f(1.8) / 0.25 = 102 – 50.96 / 0.25 = 204.16

Єt = 283 – 204.16 / 283 = 27.86%

Finally, centered divided difference is obtain by inserting f(xi+1) and f (xi-1):

F’(2) = f(2.25) – f(1.8) /2 x 0.25 = 320.84 -50.96 / 0.5 = 539.68

Єt = 283 – 539.68 / 283 = -90.7%

6 0

2 years ago

Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o

alekssr [168]

Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

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2 years ago

Classify the following random variables as discrete or continuous: X: the number of automobile accidents per year in Virginia. Y

Bess [88]

Answer:

X: Discrete random variable

Y: Continuous random variable

M: Continuous random variable

N: Discrete random variable

P: Discrete random variable

Q: Continuous random variable

Step-by-step explanation:

A discrete random variable is a variable that takes countable values such as 0,1,2,3, etc. A continuous random variable is a variable that takes measurable values such as 0.1,1.3,2.6,3.8, etc.

X,N and P are discrete random variables because they have countable values such that Number of automobile accidents,number of eggs laid and number of building permits can be counted as 0,1,2,3, and so on.

Y,M and Q are continuous random variables because they don't have countable values such that the length of time to play,the amount of milk produced and the weight of grain can be measured but can't be counted.

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2 years ago