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Finger [1]
2 years ago
15

Classify the following random variables as discrete or continuous: X: the number of automobile accidents per year in Virginia. Y

: the length of time to play 18 holes of golf. M: the amount of milk produced yearly by a particular cow. N: the number of eggs laid each month by a hen. P: the number of building permits issued each month in a certain city. Q: the weight of grain produced per acre.
Mathematics
1 answer:
Bess [88]2 years ago
8 0

Answer:

X: Discrete random variable

Y: Continuous random variable

M: Continuous random variable

N: Discrete random variable

P: Discrete random variable

Q: Continuous random variable

Step-by-step explanation:

A discrete random variable is a variable that takes countable values such as 0,1,2,3, etc. A continuous random variable is a variable that takes measurable values such as 0.1,1.3,2.6,3.8, etc.

X,N and P are discrete random variables because they have countable values such that Number of automobile accidents,number of eggs laid and number of building permits can be counted as 0,1,2,3, and so on.

Y,M and Q are continuous random variables because they don't have countable values such that the length of time to play,the amount of milk produced and the weight of grain can be measured but can't be counted.

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Let x =  the number of spruce trees
Let y =  the number of maple trees

The information given is summarized in the following table.
Number  Cost/tree  Area used   CO₂ absorption
-----------   -------------   ---------------  ----------------------
      x         $30           600 ft²         650 lb/yr
      y         $40           900 ft²         300 lb/yr

The amount available to spend is $2100, therefore
30x + 40y ≤ 2100
or
(3/4)x + y ≤ 52.5                (1)

The land available for planting is 45,000 ft², therefore
600x + 900y ≤ 45000
or
(2/3)x + y ≤ 50                    (2)
     
The amount of CO₂ removed per year is
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The shaded area in the graph shown below is the solution region.
Optimum values of A occur at the vertices, as shown.
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2 years ago
Research reports indicate that surveillance cameras at major intersections dramatically reduce the number of drivers who barrel
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Answer:

(a)Increasing

(b)t=1.34 years

(c)16 cameras per year

Step-by-step explanation:

Given the function

N(t) = 5.85t³-23.43t²+45.06t+69.5, 0≤t≤4

(a)N(0)=5.85(0)³-23.43(0)²+45.06(0)+69.5=69.5

N(4)=5.85(4)³-23.43(4)²+45.06(4)+69.5=249.26

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Since in the interval (0,4), N(0)<N(4), we say the function is increasing.

(b)The number of communities using surveillance cameras at intersections changed least rapidly at the point where the derivative of the function is zero.

N(t) = 5.85t³-23.43t²+45.06t+69.5

N'(t)=17.49t²-46.86t+45.06

If N'(t)=0,

17.49t²-46.86t+45.06=0

Solving the quadratic equation gives the values of t as:

t=1.3396-0.8842i

t=1.3396+0.8842i

We take the Real Part as our Minimum value,

The time when number of communities using surveillance cameras at intersections changed least rapidly is:

t=1.34(to 2 decimal places)

(c)Rate of Increase using a security camera/year.

N'(t)=17.49t²-46.86t+45.06

N'(t)=17.49(1)²-46.86(1)+45.06

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