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myrzilka [38]
2 years ago
10

Jerome ate 4/11 of the Pizza how much did that leave for Zachary​

Mathematics
1 answer:
ratelena [41]2 years ago
5 0

Answer:

7/11 of the Pizza was left for Zachary.

Step-by-step explanation:

Zachary had 1 - 4/11

= 11/11 - 4 /11

= 7/11.

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Last week, you spoke with 800 customers in 40 hours."
Masteriza [31]
The answer would be 20 im pretty sure
7 0
2 years ago
A plane intersects a prism parallel to the base of the prism. The cross section is a polygon with eight sides. The base of the p
Ksenya-84 [330]
I'm not quite sure but I believe the answer to your question is 4 sides
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2 years ago
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An employee compiled sales data for a company once each month. The scatter plot below shows the sales (in multiples of $1000) fo
ss7ja [257]

Answer:

$50,100

Step-by-step explanation:

Given the scatter plot and the linear model, we can estimate that the total sales for the company after 40 months will be close to $50,000.  However, in order to get a more precise answer, we can solve for the total sales, 'y', based on the number of months, 'x', in the given linear model:

y = 0.94(40) + 12.5  = 37.6 + 12.5 = 50.1

Since the amount of sales is in multiples of $1000:

50.1 * 1,000 = $50,100

3 0
2 years ago
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The first term of a finite geometric series is 6 and the last term is 4374. The sum of all the term os 6558. find the common rat
Oliga [24]

A geometric series is written as ar^n, where a is the first term of the series and r is the common ratio.

In other words, to compute the next term in the series you have to multiply the previous one by r.

Since we know that the first time is 6 (but we don't know the common ratio), the first terms are

6, 6r, 6r^2, 6r^3, 6r^4, 6r^5, \ldots.

Let's use the other information, since the last term is 4374 > 6, we know that r>1, otherwise the terms would be bigger and bigger.

The information about the sum tells us that

\displaystyle \sum_{i=0}^n 6r^i = 6\sum_{i=0}^n r^i = 6558

We have a formula to compute the sum of the powers of a certain variable, namely

\displaystyle \sum_{i=0}^n r^i = \cfrac{r^{n+1}-1}{r-1}

So, the equation becomes

6\cfrac{r^{n+1}-1}{r-1} = 6558

The only integer solution to this expression is n=6, r=3.

If you want to check the result, we have

6+6*3+6*3^2+6*3^3+6*3^4+6*3^5+6*3^6 = 6558

and the last term is

6*3^6 = 4374

7 0
2 years ago
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
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