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olasank [31]
2 years ago
12

A wireless garage door opener has a code determined by the up or down setting of 17 switches. How many outcomes are in the sampl

e space of possible codes?
Mathematics
1 answer:
pickupchik [31]2 years ago
4 0

Answer:

<em>There are 131072 outcomes possible codes in the sample space.</em>

Step-by-step explanation:

Number of switches: 17

Switch possition: 2(up or down)

The outcomes in the sample space is given by:

S=2^{17}=131072<em />

<em>There are 131072 outcomes possible codes in the sample space.</em>

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The Florida Everglades welcomes about 2x10 to the third power visitors per day. Based on this, about how many visitors come to t
Harrizon [31]
2,000 is the correct answer I am sure of it
7 0
2 years ago
A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume
mixer [17]

Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

P(W)=0.80

Then the probability that the player losses is,

P(L)=1-P(W)=1-0.80=0.20

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = 1-P(L)-P(WL)

                                    =1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let <em>X</em> = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable X\sim Bin(n=3, p=0.4096)

The probability distribution of binomial is:

P(X=x)={n\choose x}p^{x} (1-p)^{n-x}

The probability that the player defeats all the 4 opponents at least once is,

P (<em>X</em> ≥ 1) = 1 - P (<em>X</em> < 1)

             = 1 - P (<em>X</em> = 0)

             =1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0
2 years ago
A model of a building was built to a scale of 1:65.5. One side of the model is 23 inches long. How long, in feet, is this side o
umka21 [38]
130ft: you would need to do 65.5 x 23 to get 1506.5 but this is in inches, not ft so you need to convert this, which means that you need to divide 1506.5 by 12 which gets 125.54..... and round that to the nearest tenth, which leaves you with 130ft

hope this helps 
5 0
2 years ago
Please help me asap! Could you please explain how you got the answer
svetoff [14.1K]

Answer:

B) 23

Step-by-step explanation:

Table:          <u>  Algebra | No algebra | Total</u>

Physics        |      4           Step 1: 8      12

No physics  |Step 2: 15

Total            |      19                              30

We look for the number of people who are in algebra and no physics or physics and no algebra.

1. 12 - 4 = <em>8</em>

2. 19 - 4 = <em>15</em>

3. We find the total of those numbers: <em>15 + 8 =</em> 23

7 0
2 years ago
David received his allowance on Sunday. He spends 1/4 of his allowance on Monday and 2/3 of the remainder on Tuesday. What part
Marianna [84]

Answer:1/12 left

Step-by-step explanation: you should switch both into the same denominator for the fractions so that would turn into 3/12 and 8/12 then add them up to get 11/12 so he has 1/12 left

3 0
2 years ago
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